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3 years ago

If the actual concentration of the HCl was 0.33M what is your percent error?

Chemistry

1 answer:

aleksley [76]3 years ago

6 0

Answer:

The appropriate solution is "6.818".

Explanation:

The given value is:

Concentration of HCl (Actual value),

= 0.33 M

Concentration of HCl (Experimental value),

= 0.3515 M

Now,

The percentage error (%) will be:

= $\frac{Experimental \ value-Actual \ value}{Actua \ value}\times 100$

On substituting the given values, we get

= $\frac{0.3532-0.33}{0.33}\times 100$

= $\frac{0.0225}{0.33}\times 100$

= $0.06818\times 100$

= $6.818$

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