Answer:
Light is used by plants in a complex system that uses the light and several other resources to produce food. The more food= the more the plant grows, but too much food can be unhealthy for the plant. Some plants require more energy and others require less, this is because of the environment that they are in.
Explanation:
Answer:
The product is cyclohexanol
Explanation:
Firstly,
A ketone undergo a borohydride reduction reaction to form an alcohol as below,
R-CO-R' ⇒ R-CO(OH)-R'
- IR Spectrum confirms that alcohol group is existed with the peak at 3400 cm⁻¹
- From 1H-NMR, the product has 10 hydrogen atoms, the MS suggest that the formula is C₅H₁₀O (M = 86). With this formula, the alcohol is monosaturated. Since, the substance already underwent reduction reaction, the only way to suggest a monosaturated compound is a cyclic alcohol. So the compound is cyclopentanol.
- Check with other spectroscopic properties,
- 3 signals of 13C NMR confirms the structure is symmetrical, δ 24.2, (-<u>C</u>H₂-CH₂-CH(CH₂-)-OH), δ 35.5 (-CH₂-<u>C</u>H₂-CH(CH₂-)-OH), δ 73.3 (-CH₂-CH₂-<u>C</u>H(CH₂-)-OH).
1.56 δ (4H, triplet) - (-C<u>H</u>₂-CH₂-CH-OH) ; triplet as coupling with 2 H,
1.78 δ (4H, multiplet) - (-CH₂-C<u>H</u>₂-CH-OH); multiplet as coupling with 2H of CH₂, 1 H of CH
3.24 δ (1H, quintet); - (-CH₂-CH₂-C<u>H</u>(CH₂-)-OH), coupling with4 H of 2 group of CH₂
3.58 δ (1H, singlet); - (-CH₂-CH₂-CH(CH₂-)-O<u>H</u>), hydrogen of alcohol group, not tend to coupling with other hydrogen
Answer:
1. Compound A is propanol which reacts with sodium metal with the evolution of hydrogen gas and this is the gas which is causing little explosion. Propanol is normally liquid at room temperature.
2. Compound B is propene since it decolourises bromine water. This reaction is normally an addition reaction.
3. Compound C is propane since it gives a substitution reaction with chlorine.
Explanation:
Answer:
The correct answer is 0.75 atm
Explanation:
We have carbon monoxide gas (CO) at the following conditions:
T= 30ºC = 303 K
V= 20.0 L
m = 17 g
The molecular weight of CO (MM CO) is the following:
MM CO= molar mass of C + molar mass of O = 12 g/mol + 16 g/mol = 28 g/mol
We calculate the number of moles (n) as follows:
n= m/MM CO = 17 g/28 g/mol = 0.61 mol
Finally we use the ideal gases equation to calculate the pressure (P):
P x V = n x R x T
P = (n x R x T)/V
P= (0.61 mol x 0.082 L.atm/K.mol x 303 K)/20.0 L
P= 0.75 atm
Ocean acidification is occurring because excess carbon dioxide (CO2) in the atmosphere is being absorbed at the surface of the ocean at an increasing rate. This excess CO2 results in more hydrogen ions, which increases the acidity of the ocean.