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STatiana [176]
3 years ago
8

Which layer is the oldest layer? How can you tell? ​

Chemistry
2 answers:
Neporo4naja [7]3 years ago
6 0

Answer:

The principle of superposition states that the oldest rock units are at rock bottom , and therefore the youngest are at the highest . Based on this, layer C is oldest, followed by B and A. So the full sequence of events is as follows: Layer C formed.

Explanation:

aleksley [76]3 years ago
3 0

Answer:

the lowest one

the same way when you are stacking plates the oldest one is at the bottom and the most recently stacked one is at the top

Explanation:

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Chemical formula of ammonium oxide
11111nata11111 [884]

The answer is (NH4)2O

8 0
3 years ago
In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2
valentinak56 [21]

The percent yield of the reaction : 89.14%

<h3>Further explanation</h3>

Reaction of Ammonia and Oxygen in a lab :

<em>4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)</em>

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

\dfrac{80}{17}=4.706

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{120}{32}=3.75

Mol ratio of reactants(to find limiting reatants) :

\tt \dfrac{4.706}{4}\div \dfrac{3.75}{5}=1.1765\div 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

\tt \dfrac{6}{5}\times 3.75=4.5

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%

6 0
3 years ago
The order of components in a typical flame atomic absorption spectrometer is
Zinaida [17]

The order of components in a typical flame atomic absorption spectrometer is hollow cathode lamp--flame--monochromator--detector

<u>Explanation:</u>

  • The hollow cathode lamp practices a cathode created of the element of interest with a low internal pressure of inert gas.
  • Remove scattered light of other wavelengths from the flame. AAS flame includes aiming at first the fuel than the oxidant and then lighting the flame with the instrument's auto-ignition system. Applying flame Ddtroy any analyte ions and breakdown complexes.
  • The process  of the monochromator is to divide analytical lines photons moving through the flame
  • Photomultiplier tube (PMT)  as the detector the PMT determines the intensity of photons of the analytical line exiting the monochromator.
4 0
3 years ago
What is the density of an object with a mass of 16 g and 3.0 ml
fomenos

Answer:

D = 5.3 g/mL

Explanation:

Density = Mass over Volume

D = m/V

Step 1: Define

D = unknown

m = 16 g

v = 3.0 mL

Step 2: Substitute and Evaluate

D = 16 g / 3.0 mL

D = 5.333333333 g/mL

Step 3: Simplify

We have 2 sig figs.

5.333333333 g/mL ≈ 5.3 g/mL

6 0
3 years ago
A sample of chlorine gas occupies a volume of 707 ml at 2.90 atm. What is the new pressure in torr if the volume is compressed t
dolphi86 [110]

Answer:

The new pressure is 3850 torr.  

Explanation:

The relation between volume and pressure is inverse as per Boyle's law. Its mathematical form is given by :

P_1V_1=P_2V_2

Here,

P_1=2.9\ atm

V_1=707\ mL

V_2=0.533\ L

Let P_2 is the new pressure. So using Boyle's law we get :

P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{2.9\times 707}{0.533}\\\\P_2=3846.71\ \text{torr}

or

P_2=3850\ \text{torr}

So, the new pressure is 3850 torr.  

3 0
3 years ago
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