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mojhsa [17]
4 years ago
14

develop a hypothesis to explain why the radiation from the 14C source could be shielded more effectively than the radiation from

the 137Cs source. what do your results suggest about the decay mode of each radioactive isotope?
Chemistry
1 answer:
Hoochie [10]4 years ago
4 0
<span>The results suggests that </span>¹³⁷C  is more radioactive and decays faster than ¹⁴C. Also ¹³⁷C penetrates more than ¹⁴C because it has both beta and gamma particle unlike ¹⁴C which has only a beta particle. Gamma particle passes to any kind of material be it fiber glass or metal unlike a beta particle, it cannot pass through these materials.
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Answer:

  • 90.4 liter

Explanation:

You must convert the 6.00 grams of H₂ into number of moles, and then use the stoichiometry of the reaction to find the number of moles of NH₃, which can be converted into volume using the ideal gas equation.

<u></u>

<u>1. Number of moles of H</u><u>₂</u>

  • number of moles = mass in grams / molar mass
  • molar mass of H₂ = 2.016g/mol
  • number of moles = 6.00grams / 2.016g/mol = 2.97619mol

<u></u>

<u>2. Number of moles of NH</u><u>₃</u>

<u></u>

i) Chemical equation:

  • 3H₂(g) + N₂(g) →  2NH₃(g)

ii) Mole ratio:

  • 3 mol H₂ : 2 mol NH₃

iii) Proportion:

  • x mol  NH₃ / 2.97619mol H₂ = 3 mol NH₃ / 2 mol H₂

  • x = 4.4642857mol NH₃

<u>3. Volume of NH₃</u>

  • pV = nRT
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  • V = 4.4642857mol × 0.08206 atm·liter/(K·mol) × 506K / 2.05atm
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