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astra-53 [7]
2 years ago
8

I need help please . science

Chemistry
2 answers:
dlinn [17]2 years ago
8 0

Answer:

Whats that supposed to mean?

whats the question

Explanation:

vladimir2022 [97]2 years ago
4 0
We need to question!!
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Triethylenemelamine is used in the plastics industry and as an anticancer drug. Its analysis is 52.93% carbon, 5.92 % hydrogen,
patriot [66]

Assuming total mass to be 100 g

Mass of C = 52.93 g

=> Moles of C = 52.93 g *\frac{1 mol}{12gC} =4.41 mol C

Mass of H = 5.92 g

=> Moles of H=5.92g*\frac{1mol}{1.01g}=5.86molH

Mass of N = 41.15 g

=>Moles of N=41.15g*\frac{1 mol}{14 g}=2.94mol N

Simplest mole ratio of the atoms in the compound:

C_{\frac{4.41mol}{2.94mol} } H_{\frac{5.86mol}{2.94mol} }N_{\frac{2.94mol}{2.94mol} } =C_{1.5}H_{2}N_{1} or(C_{1.5}H_{2}N_{1})_{2}=>C_{3}H_{4}N_{2}

Empirical formula mass=(3*12)+(4*1.01)+(2*14)=68.04g

Multiple n = \frac{204.2}{68.04}=3

Molecular formula= (Empirical formula)_{n} =(C_{3}H_{4}N_{2})_{3}=C_{9}H_{12}N_{6}


6 0
3 years ago
How many molecules of CH4 are in 24.1 g of this compound?
jok3333 [9.3K]

<u>1) find molar mass of CH₄</u>

=12.01+4(1.01)\\\\=16.05\ g/mol

<u>2) determine moles of CH₄</u>

=24.1g\ CH_{4}\ x\ \frac{1\ mol\ CH_{4}}{16.05g\ CH_{4}}\\\\=1.501557632\ mol\ CH_{4}

<u>3) multiply by avogadro's number</u>

=1.501557632\ mol\ CH_{4}\ x\ \frac{6.022\ x\ 10^{23}\ molecules\ CH_{4}}{1\ mol\ CH_{4}} \\\\=9.04238006\ x\ 10^{23}\\\\=9.04\ x\ 10^{23}\ molecules\ CH_{4}

7 0
2 years ago
Given that a for HCN is 6. 2×10^−10 at 25 °C. What is the value of b for cn− at 25 °C?
Kay [80]

If Ka for HCN is 6. 2×10^−10 at 25 °C, then the value of Kb for cn− at 25 °C is 1.6 × 10^(-5).

<h3>What is base dissociation constant? </h3><h3 />

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 6.2× 10^(-10)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{6.2×10^(-10) }

= 1.6× 10^(-5)

Thus, the value of base dissociation constant at 25°C is 1.6 × 10^(-5).

learn more about base dissociation constant :

brainly.com/question/9234362

#SPJ4

4 0
2 years ago
A solution of [FeSCN]^{2+} is found to have 37% transmittance at 447 nm. If the molar absorption coefficient (ε) is 4400 at λ_{m
alexandr1967 [171]

Answer:9.81×10^-5 M

Explanation: See attachments

8 0
3 years ago
What term refers to the coldest and densest zone, deep below the surface of a lake?
uranmaximum [27]
Profundal 

profundal zone is the coldest and deepest zone 
5 0
3 years ago
Read 2 more answers
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