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3 years ago

A substance has a solubility of 350 ppm.how many grams of the substance are present in 1.0l of a saturated solution

Chemistry

2 answers:

Kazeer [188]3 years ago

8 0

Answer:

0.350 grams of the substance are present in 1.0l of a saturated solution

Explanation:

Parts per million (ppm), is a unit of measurement for concentration. Refers to the number of units of the substance per million units of the set.

So ppm means parts per million, that is, the mg (milligrams) in a kg of solution.

Considering that the density of a substance is 1000 kg / m3 (and 1 m3 is 1000 L), 1 kg of solution has a volume of approximately 1 liter, ppm also represents the mg of a substance in a liter of solution. That is, 1 ppm = 1 mg / L.

So in 1 L there are 350 mg of substance present. Being 1 g = 1000 mg, then 350 mg is 0.350 g.

0.350 grams of the substance are present in 1.0l of a saturated solution

sergeinik [125]3 years ago

6 0

Since the given solubility is 350 ppm, convert it first with fraction of solubility. by dividing the solubility with 10^6
S = 350 / 10^6
s = 3.5 x 10^-4
the multiply it to the total solution to calculate the amount of substance present
m = ( 3.5 x 10^-4 ) ( 1.01 )
m = 3.535 x 10^-4 g of the substance present

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Answer:

81.3%

Explanation:

Step 1:

The balanced equation for the reaction:

This is shown below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Step 2:

Data obtained from the question. This includes:

Mass of propane (C3H8) = 470 g

Actual yield of water (H2O) = 625 g

Percentage yield of water (H2O) =?

Step 3:

Determination of the mass of propane (C3H8) burned and the mass of water (H2O) produce from the balanced equation. This is illustrated below:

C3H8 + 5O2 —> 3CO2 + 4H2O

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Mass of H2O from the balanced equation = 4 x 18 = 72g

From the balanced equation above,

44g of C3H8 was burned and 72g of H2O was produced.

Step 4:

Determination of the theoretical yield of H2O. This is illustrated below:

From the balanced equation above,

44g of C3H8 produced 72g of H2O.

Therefore, 470g of C3H8 will produce = (470x72)/44 = 769.09g of H2O.

Therefore, the theoretical yield of H2O is 769.09g

Step 5:

Determination of the percentage yield of water (H2O). This is illustrated below:

Actual yield of water (H2O) = 625g

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Percentage yield = Actual yield/Theoretical yield x100

Percentage yield = 625/769.09 x100

Percentage yield = 81.3%

Therefore, the percentage yield of water (H2O) is 81.3%

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