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ElenaW [278]
3 years ago
10

If you stung by a honey bee. why we suggest rub with baking soda why?​

Physics
2 answers:
AnnZ [28]3 years ago
7 0
Cause we believe as humans that r
pickupchik [31]3 years ago
3 0

Answer:

When a bee stings, it injects methanoic acid into the skin which causes immense pain and irritation. Rubbing of baking soda on the sting area gives relief because, being alkaline in nature, baking soda neutralizes the effect of methanoic acid and gives relief.

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Which statement correctly compares sound and light waves ​
kolbaska11 [484]

Answer:

Light waves carry energy parallel to the motion of the wave, while sound waves carry energy perpendicular to it. Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.

Explanation:

8 0
3 years ago
According to Newton's law of motion, when we shake a mango tree, mangoes fall down explain.​
Reptile [31]
When we shake a mango tree, the mangoes fall down. It is because when we shake the tree, the mango tend to be rest due to inertia where as the branches are in motion. That is why the mangoes tend to be at rest due to inertia where as the branches are in the motion.
8 0
3 years ago
One of the light bulbs in this series circuit burns out, causing a break in the circuit.
ivanzaharov [21]

Answer:

It doesn't give light

Explanation:

No Flowing of electricity

3 0
2 years ago
An earthquake’s epicenter is _____.
Evgen [1.6K]
The point in which it originates.
4 0
3 years ago
Read 2 more answers
Two transverse waves travel along the same taut string. Wave 1 is described by y1(x, t) = A sin(kx - ωt), while wave 2 is descri
Vadim26 [7]

Answer:

6) Wave 1 travels in the positive x-direction, while wave 2 travels in the negative x-direction.

Explanation:

What matters is the part kx \pm \omega t, the other parts of the equation don't affect time and space variations. We know that when the sign is - the wave propagates to the positive direction while when the sign is + the wave propagates to the negative direction, but <em>here is an explanation</em> of this:

For both cases, + and -, after a certain time \delta t (\delta t >0), the displacement <em>y</em> of the wave will be determined by the kx\pm\omega (t+\delta t) term. For simplicity, if we imagine we are looking at the origin (x=0), this will be simply \pm \omega (t+\delta t).

To know which side, right or left of the origin, would go through the origin after a time \delta t (and thus know the direction of propagation) we have to see how we can achieve that same displacement <em>y</em> not by a time variation but by a space variation \delta x (we would be looking where in space is what we would have in the future in time). The term would be then k(x+\delta x)\pm\omega t, which at the origin is k \delta x \pm \omega t. This would mean that, when the original equation has kx+\omega t, we must have that \delta x>0 for k\delta x+\omega t to be equal to kx+\omega\delta t, and when the original equation has kx-\omega t, we must have that \delta x for k\delta x-\omega t to be equal to kx-\omega \delta t

<em>Note that their values don't matter, although they are a very small variation (we have to be careful since all this is inside a sin function), what matters is if they are positive or negative and as such what is possible or not .</em>

<em />

In conclusion, when kx+\omega t, the part of the wave on the positive side (\delta x>0) is the one that will go through the origin, so the wave is going in the negative direction, and viceversa.

4 0
3 years ago
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