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Firdavs [7]
3 years ago
8

1. Explain who is doing more work and why: a bricklayer carrying bricks and placing them on the wallof a building being

Physics
1 answer:
Basile [38]3 years ago
7 0
Both are doing because they have chorus
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4 years ago
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What does 9.8 m/s/s have to do with acceleration?
ruslelena [56]

9.8 is the gravitational field strength on earth, perhaps re-read the question

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A bicyclist moves along a straight line with an initial velocity vo and slows downs. Which of the following the best describes t
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3 years ago
A car with mass m-1000 kg completes a turn of radius r 540 m at a constant speed of v =25 m/s. As the car goes around the turn,
Nataly [62]

Answer:

friction coefficient on the rough road is 0.117

Explanation:

As we know that car is taking turn on flat rough road

So here we can say that required centripetal force for circular motion of car is due to frictional force

So we have

F_c = \frac{mv^2}{R}

now we have

\mu mg = \frac{mv^2}{R}

so we have

\mu = \frac{v^2}{Rg}

\mu = \frac{25^2}{540(9.81)}

\mu = 0.117

6 0
4 years ago
You push a 1.30 kg physics book 2.80 m along a horizontal tabletop with a horizontal push of 1.55 N while the opposing force of
Rzqust [24]

Answer:

<h2>3.36J</h2>

Explanation:

Step one:

given data

mass m= 1.3kg

distance moved s= 2.8m

opposing frictional force= 0.34N

assume g= 9.81m/s^2

we know that work done= force *distance moved

1. work done to push the book= 1.55*2.8=4.34J

2. Work against friction = force of friction x distance

                                       = 0.34*2.8=0.952J

Step two:

the work done on the book is the net work, which is

Network done= work done to push the book- Work against friction

Network done= 4.32-0.952=3.36J

<u>Therefore the work of the 1.55N 3.36J</u>

4 0
3 years ago
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