I think it’s D
I hope this hopes
9.8 is the gravitational field strength on earth, perhaps re-read the question
Answer:
friction coefficient on the rough road is 0.117
Explanation:
As we know that car is taking turn on flat rough road
So here we can say that required centripetal force for circular motion of car is due to frictional force
So we have

now we have

so we have



Answer:
<h2>3.36J</h2>
Explanation:
Step one:
given data
mass m= 1.3kg
distance moved s= 2.8m
opposing frictional force= 0.34N
assume g= 9.81m/s^2
we know that work done= force *distance moved
1. work done to push the book= 1.55*2.8=4.34J
2. Work against friction = force of friction x distance
= 0.34*2.8=0.952J
Step two:
the work done on the book is the net work, which is
Network done= work done to push the book- Work against friction
Network done= 4.32-0.952=3.36J
<u>Therefore the work of the 1.55N 3.36J</u>