List five situations in which temporary wiring would be used

If a curve with a radius of 65 m is properly banked for a car traveling 75 km/h, what must be the coefficient of static friction

STALIN [3.7K]

As a car makes a turn, the force of friction acting upon the turned wheels of the car provides centripetal force required for circular motion. Equation to follow are F = mv²/r "Force of friction" Ff= μsN, Normal N=mg Ff=μsmg. Therfore
mv²/r = μsmg cancel mass "m" The formula to follow will be μs = v²/rg

μs = v²/rg μs = (28.89 m/s²)²/ (65 m)(9.8 m/s²) = 1.31

8 0

4 years ago

Two particles having charges of 0.440 nC and 11.0 nC are separated by a distance of 1.80 m . 1) At what point along the line con

Harlamova29_29 [7]

Answer:

a) 0.3 m

b) r = 0.45 m

Explanation:

given,

q₁ = 0.44 n C and q₂ = 11.0 n C

assume the distance be r from q₁ where the electric field is zero.

distance of point from q₂ be equal to 1.8 -r

now,

E₁ = E₂

$\dfrac{K q_2}{(1.8-r)^2} = \dfrac{K q_1}{r^2}$

$(\dfrac{1.8-r}{r})^2= \dfrac{q_2}{q_1}$

$\dfrac{1.8-r}{r}= \sqrt{\dfrac{11}{0.44}}$

1.8 = 6 r

r = 0.3 m

<h3>b) zero when one charge is negative.</h3>

let us assume q₁ be negative so, distance from q₁ be r

from charge q₂ the distance of the point be 1.8 +r

now,

E₁ = E₂

$\dfrac{K q_2}{(1.8+r)^2} = \dfrac{K q_1}{r^2}$

$(\dfrac{1.8+r}{r})^2= \dfrac{q_2}{q_1}$

$\dfrac{1.8+r}{r}= \sqrt{\dfrac{11}{0.44}}$

1.8 =4 r

r = 0.45 m

4 0

4 years ago

A hydrogen atom contains a single electron that moves in a circular orbit about a single proton. Assume the proton is stationary

riadik2000 [5.3K]

Answer:

Radius between electron and proton $= 6.804\times 10^{-10}m$

Explanation:

The motion of the electron is carried out in the orbit due to the balancing of the electrostatic force between the proton and the electron and the centripetal force acting on the electron.

The electrostatic force is given as = $\frac{kq_1q_2}{r^2}$

Where,

k = coulomb's law constant (9×10⁹ N-m²/C²)

q₁ and q₂ = charges = 1.6 × 10⁻¹⁹ C

r = radius between the proton and the electron

Also,

Centripetal force on the moving electron is given as:

= $\frac{m_eV^2}{r}$

where,

$m_e$ = mass of the electron (9.1 ×10⁻³¹ kg)

V = velocity of the moving electron (given: 6.1 ×10⁵ m/s)

Now equating both the formulas, we have

$\frac{kq_1q_2}{r^2}$ = $\frac{m_eV^2}{r}$

⇒ $r = \frac{kq_1q_2}{m_eV^2}$

substituting the values in the above equation we get,

$r = \frac{9\times 10^{9}\times (1.6\times 10^{-19})^2}{9.1\times 10^{-31}\times (6.1\times 10^5)^2}$

⇒ $r = 6.804\times 10^{-10}m$

3 0

3 years ago

In the Boyle’s law experiment, what was used to increase the pressure on the air (gas)?

MA_775_DIABLO [31]

Answer:

Volume.

Explanation:

Boyle’s law experiment :

This is also known as Mariotte's law or in the other words it is also known as Boyle–Mariotte law.

This law tell us about the variation of gas pressure when the volume of the gas changes at the constant temperature.According to this law the abslute pressure is inversely proportional to the volume .

We can say that

$P\alpha \dfrac{1}{V}$

Where P=Pressure

V=Volume

PV = K

K=Constant

When volume decrease then the pressure of the gas will increase.

That is why the answer is "Volume".

8 0

3 years ago

Choose the true statement concerning the mass of subatomic particles.A.Electrons are more massive than protons.B.Electrons are m

Degger [83]

Answer is C. Because protons and neutrons are more massive then electrons so that means A and b and C are not right

4 0

4 years ago

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