Question

In a quad ABCD Angle A 2x+35 angle B 3x-5 Angle C x+10 Angle D 4x+20 what is the value of x​

Answer 1

Answer:

x = $30^{o}$

Explanation:

The sum of the interior angles of a quadrilateral is $360^{o}$, so that from the given question:

<A + <B + <C + <D = $360^{o}$

(2x + 35) + (3x - 5) + (x + 10) + (4x + 20) = $360^{o}$

10x + 60 = $360^{o}$

10x = $360^{o}$ - 60

     = 300

x = $\frac{300}{10}$

  = 30

x = $30^{o}$

So that,

<A = (2x + 35) = (2*30 + 35) = $95^{o}$

<B = (3x - 5) = (3*30 - 5) = $85^{o}$

<C = (x + 10) = (30 + 10) = $40^{o}$

<D = (4x + 20) = (4*30 + 20) = $140^{o}$

Thus,

$95^{o}$ + $85^{o}$ + $40^{o}$ + $140^{o}$ = $360^{o}$