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Alexxandr [17]
3 years ago
6

In a quad ABCD Angle A 2x+35 angle B 3x-5 Angle C x+10 Angle D 4x+20 what is the value of x​

Health
1 answer:
earnstyle [38]3 years ago
3 0

Answer:

x = 30^{o}

Explanation:

The sum of the interior angles of a quadrilateral is 360^{o}, so that from the given question:

<A + <B + <C + <D = 360^{o}

(2x + 35) + (3x - 5) + (x + 10) + (4x + 20) = 360^{o}

10x + 60 = 360^{o}

10x = 360^{o} - 60

     = 300

x = \frac{300}{10}

  = 30

x = 30^{o}

So that,

<A = (2x + 35) = (2*30 + 35) = 95^{o}

<B = (3x - 5) = (3*30 - 5) = 85^{o}

<C = (x + 10) = (30 + 10) = 40^{o}

<D = (4x + 20) = (4*30 + 20) = 140^{o}

Thus,

95^{o} + 85^{o} + 40^{o} + 140^{o} = 360^{o}

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