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Rom4ik [11]
3 years ago
10

Two nuclear reactors provide 3200 MW of power.If the transmission system loses 5.1% of the energy produced,how much power from t

hese two reactors would customers receive ?
Physics
1 answer:
Annette [7]3 years ago
6 0

The power that the customers receive is 163.2 MW

Explanation:

The efficiency of a system is given by

\eta = \frac{P_{out}}{P_{in}}

where

P_{out} is the power in output

P_{in} is the power in input

For the nuclear reactors in this problem, we have:

P_{in} = 3200 MW (power generated by the reactors)

\eta=0.051 (efficiency is 5.1%)

Therefore, the power that reaches the customers is:

P_{out} = \eta P_{in} = (0.051)(3200)=163.2 MW

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

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An insulated box has a barrier that confines a gas to only one side of the box. The barrier springs a leak, allowing the gas to
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Answer:

B) The entropy is greater in the second state, with the gas on both sides of the box.

Explanation:

As we know that ,this is a irreversible process .The process leaves some effect on the surrounding or on the system itself ,is known as irreversible process.But on the other hand those process does not leave any effect on the system and surrounding is known as reversible process.

The entropy in the irreversible process always increases ,that is why the the entropy will be more when gas occupy the both boxes.

Therefore the answer is --B

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3 years ago
The blackbody curve for a star named Zeta is shown below. The most intense radiation for this star occurs in what spectral band?
zmey [24]

Answer:Visible lighlight

Explanation:

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2 years ago
Two boxes on opposite ends of a massless board that is 3.0 m long. The board is supported in the middle by a fulcrum. The box on
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Answer:

b. 1.1 m

Explanation:

It is given that the total distance between the masses is equal to the length of the board, which is 3 m. Therefore,

s_{1} + s_{2} = 3\ m\\\\s_{2} = 3\ m - s_{1}\ --------- eqn(1)

where,

s₁ = distance of fulcrum from left mass

s₂ = distance of fulcrum from right mass

In order to achieve balance, the torque due to both masses must be equal:

T_{1} = T_{2}\\m_{1}s_{1} = m_{2}s_{2}\\(25\ kg)(s_{1}) = (15\ kg)(s_{2})\\\\\frac{15\ kg}{25\ kg}(s_{2}) = s_{1}\\\\using\ eqn(1):\\(0.6)(3\ m - s_{1}) = s_{1}\\1.8\ m = 1.6\ s_{1}\\s_{1} = \frac{1.8\ m}{1.6}

s₁ = 1.1 m

Hence, the correct option is:

<u>b. 1.1 m</u>

4 0
3 years ago
From a height of 40.0 m, a 1.00 kg bird dives (from rest) into a small fish tank containing 50.5 kg of water. Part A What is the
Rom4ik [11]

Answer:

0.00185 °C

Explanation:

From the question,

The potential energy of the bird = heat gained by the water in the fish tank.

mgh = cm'(Δt)................... Equation 1

Where m = mass of the bird, g = acceleration due to gravity, h = height, c = specific heat capacity of water, m' = mass of water, Δt = rise in temperature of water.

make Δt the subject of the equation

Δt = mgh/cm'............... Equation 2

Given: m = 1 kg, h = 40 m, m' = 50.5 kg

constant: g = 9.8 m/s², c = 4200 J/kg.K

Substitute into equation 2

Δt = 1(40)(9.8)/(50.5×4200)

Δt = 392/212100

Δt = 0.00185 °C

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