(a-b) X (a+b)
= aXa - bXa +aXb -bXb (distributing)
Now, cross product of a vector with itself = 0
so, aXa = 0, bXb = 0
Also, aXb = - bXa
so,
(a-b) X (a+b) = 0 + aXb + aXb + 0
= 2aXb
hence, proved :)
Answer:
a'b' and ab are the same length
Step-by-step explanation:
they are both four squares long
Answer:
87 in³
Step-by-step explanation:
that is the solution above