Following the key in the diagram (see the attached image), the only particle diagram that represents a mixture of three substances is diagram 2.
To simplify it, let us replace the key in the diagram as follows;
- atom of one element = A
- atom of different element = B
Diagram 1 consists of only AA and AB
Diagram 2 consists of AA, BB, and AB.
Diagram 3 consists of AA and ABA
Diagram 4 consists of AA and BAB
Thus, only diagram 2 has a mixture of 3 substances.
More on mixtures can be found here: brainly.com/question/6594631
Answer:
The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg
Explanation:
Data
P = 0.62 atm
P = ? kPa
P = ? mmHg
Process
1.- Look for the conversion factor of atm to kPa and mmHg
1 atm = 101.325 kPa
1 atm = 760 mmHg
2.- Do the conversions
1 atm ----------------- 101.325 kPa
0.62 atm ------------ x
x = (0,62 x 101.325) / 1
x = 62.82 kPa
1 atm ------------------ 760 mmHg
0.62 atm ------------ x
x = (0.62 x 760)/1
x = 471.2 mmHg
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