![sin^2(\theta)+cos^2(\theta)=1\qquad \qquad sin(2\theta)=2sin(\theta)cos(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=sin%5E2%28%5Ctheta%29%2Bcos%5E2%28%5Ctheta%29%3D1%5Cqquad%20%5Cqquad%20sin%282%5Ctheta%29%3D2sin%28%5Ctheta%29cos%28%5Ctheta%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![tan(x)+cot(x)=\cfrac{2}{sin(2x)} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{doing the left-hand-side}}{\cfrac{sin(x)}{cos(x)}+\cfrac{cos(x)}{sin(x)}\implies \cfrac{sin^2(x)+cos^2(x)}{\underset{\textit{using this LCD}}{sin(x)cos(x)}}} \implies \cfrac{1}{sin(x)cos(x)}](https://tex.z-dn.net/?f=tan%28x%29%2Bcot%28x%29%3D%5Ccfrac%7B2%7D%7Bsin%282x%29%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bdoing%20the%20left-hand-side%7D%7D%7B%5Ccfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%2B%5Ccfrac%7Bcos%28x%29%7D%7Bsin%28x%29%7D%5Cimplies%20%5Ccfrac%7Bsin%5E2%28x%29%2Bcos%5E2%28x%29%7D%7B%5Cunderset%7B%5Ctextit%7Busing%20this%20LCD%7D%7D%7Bsin%28x%29cos%28x%29%7D%7D%7D%20%5Cimplies%20%5Ccfrac%7B1%7D%7Bsin%28x%29cos%28x%29%7D)
now, let's recall that anything times 1 is just itself, namely 5*1 =5, 1,000,000 * 1 = 1,000,000, "meow" * 1 = "meow" and so on, so we can write anything as time 1.
let's recall something else, that same/same = 1, so

therefore

Answer: 4
Step-by-step explanation:
For any binomial variable X having parameters n (total number of trials ) and p (probability of getting success in each event), the standard deviation is given by :-

As per given , we have
n= 100 , p= 20%=0.20
Then, the standard deviation of this binomial distribution is :

Hence, the standard deviation of this binomial distribution is <u>4</u>.
Answer:
CRYBABY-Megan Thee Stallion (FT.DaBaby)
Step-by-step explanation:
SONG FYE GO LISTEN TO IT PLEASE TY !
Answer:
The answer is C. y – 9.35 = −2.95(x – 7).
Step-by-step explanation: