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Marina86 [1]
3 years ago
14

Explain why 0.76 * 103 would not be considered a correct answer for a scientific notation problem? What should be done to fix th

is? Give the correct answer.
Chemistry
2 answers:
Valentin [98]3 years ago
7 0
The decimal should be after the 7 and before the 6.
Tema [17]3 years ago
6 0

Scientific notation is always expressed as a number between 1 and 10 not including 10 followed by 10 to a power.

1 ≤ x < 10

7.6 * 10^2 is the correct answer. You used one of the powers to get to a number between 1 and 10

0.76 * 10 = 7.6 That leaves you with 2 tens.

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Which type of bond is found between atoms of solid cobalt?
Vsevolod [243]
The answer is (3) metallic. Cobalt is a transition metal, so it can't be covalent bonds, which bond non-metals, therefore eliminating choice 1 and 2. Ionic bonds are between metals and non metals, but solid cobalt does not have a non metal, eliminating choice 4 as well. Metallic bonds are bonds between metals, therefore the answer is (3) metallic.
3 0
3 years ago
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A porpoise sends out an ultrasonic burst and hears the echo off his favorite food in 0.13 seconds. How far away is the food sour
aalyn [17]

Answer:

The porpoise would hear its echo first because sound travels faster in water than in air. The bat would hear its echo first because the amplitude of sound waves ...

Explanation:

5 0
3 years ago
Determine the temperature of 1.42 mol of a gas contained in a 3.00-L container at a pressure of 123 kPa
Rashid [163]

Answer:

The temperature is 30,92K

Explanation:

We use the formula PV=nRT. We convert the unit of pressure in kPa into atm.

101,325kPa----1atm

121kPa-------x=(121,3kPax 1 atm)/101,325kPa=1, 2 atm

PV=nRT---->T= (PV)/(RT)

T=(1,2 atm x 3L)/(1,42 mol x 0,082 l atm/K mol )= 30, 91721058 K

6 0
3 years ago
Calculate the pH of the solution that results when 20 mL of 0.2M HCOOH is mixed with 25mL of 0.2M NaOH solution.(post-equivalenc
Paul [167]

The pH of the solution : 12

<h3>Further explanation</h3>

Reaction

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

mol HCOOH =

\tt 20~ml\times 0.2~M=4~mlmol

mol NaOH =

\tt 25~ml\times 0.2~M=5~mlmol

Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]

ICE method :

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

4                          5

4                          4                     4                   4

0                          1                      1                    1

Concentration of [OH⁻] from NaOH :

\tt \dfrac{1~mlmol}{20+25~ml}=0.02

pOH=-log[OH⁻]

pOH=-log 10⁻²=2

pH+pOH=14

pH=14-2=12

3 0
3 years ago
I WILL MARK YOU BRAINLYEST
Agata [3.3K]

Answer:

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Explanation:

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