Answer:
The percentage yield is= 80%
Explanation:
% yield= actual yield/theoretical yield ×100
From The question
Actual yield= 240mg
Theoretical yield= 300mg
%yield= 240/300×100= 80%
Answer:
the entropy change of the fluid during the process process is is 1.337 kJ/K, the change for the source is -1.337 kJ/K and the total entropy change is 0
Explanation:
since the Carnot cycle is a reversible cycle, the entropy change is related with the heat exchanged through:
ΔS =∫dQ/T
since the temperature remains constant
ΔS =∫dQ/T=(1/T)*∫dQ = Q/T
Q= heat added to the system
T= absolute temperature = 400°C= 673 K
therefore
ΔS = Q/T = 900 kJ/ 673 K = 1.337 kJ/K
ΔS working fluid = 1.337 kJ/K
since the process is reversible, the entropy change of the universe (total entropy change) is 0 (there is no entropy generation). thus
ΔS universe = ΔS working fluid + ΔS source = 0
ΔS source= -ΔS working fluid = -1.337 kJ/K
Answer:
- <u><em>B. Negative association</em></u>
<u><em></em></u>
Explanation:
<em>Negative association</em> is when the independent and dependent variables move in opposite directions: if the dependent variable increases, the independent variable decreases, and if the dependent variable decreases, the independent variable increases.
As you see in the diagram, as you move to the right on the horizontal axis, meaning that the independent variable is increasing, the points lie lower, meaning that the independent variable decreases.
Therefore, if you draw a line of best fit, it will have a negative slope. A negative slope indicates <em>negative association.</em>
The graph certainly shows association as there is a clear trend; else the points would be randomly dispersded.
Answer:
V = 65.81 L
Explanation:
En este caso, debemos usar la expresión para los gases ideales, la cual es la siguiente:
PV = nRT (1)
Donde:
P: Presion (atm)
V: Volumen (L)
n: moles
R: constante de gases (0.082 L atm / mol K)
T: Temperatura (K)
De ahí, despejando el volumen tenemos:
V = nRT / P (2)
Sin embargo como estamos hablando de condiciones normales de temperatura y presión, significa que estamos trabajando a 0° C (o 273 K) y 1 atm de presión. Lo que debemos hacer primero, es calcular los moles que hay en 50 g de amoníaco, usando su masa molar de 17 g/mol:
n = 50 / 17 = 2.94 moles
Con estos moles, reemplazamos en la expresión (2) y calculamos el volumen:
V = 2.94 * 0.082 * 273 / 1
<h2>
V = 65.81 L</h2>
Answer:
Volume would be 13
Explanation:
Divide the mass by the density
65/5
