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Lady_Fox [76]
3 years ago
11

In an electrical circuit, what happens to the current flowing through the wire if the initial voltage of 18 V is doubled, and th

e initial resistance of 35 Ohms is reduced by a factor of 4?
ANSWER QUICKLY PLEASE! ITS URGENT!
Physics
2 answers:
Evgen [1.6K]3 years ago
5 0

Answer:

I hope this helps you :)

Explanation:

The current is directly proportional to the voltage and inversely proportional to the resistance. ... So doubling or tripling the resistance will cause the current to be one-half or one-third of the original value.

Genrish500 [490]3 years ago
3 0

The current is increased by a factor of 8.

From 18/35 A. to 144/35 A.

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From the top of a cliff, a person tosses a pebble straight downward with an initial velocity of -9.0 meters/second. After 0.50 s
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galina1969 [7]

Question:

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

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Answer:

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Explanation:

From the question

Length of wire (L) = 2.80 m

Current in wire (I) = 5.20 A

Magnetic field (B) = 0.430 T

Angle are different in each part.

The magnetic force is given by

F=I \times B \times L \times sin(\theta)

So from data

F = 5.20 A \times 0.430 T \times 2.80 sin(\theta)\\\\F=6.2608 sin(\theta) N

Now sub parts

(a)

\theta=60^{o}\\\\Force = 6.2608 sin(60^{o}) N\\\\Force = 5.42 N

(b)

\theta=90^{o}\\\\Force = 6.2608 sin(90^{o}) N\\\\Force = 6.26 N

(c)

\theta=120^{o}\\\\Force = 6.2608 sin(120^{o}) N\\\\Force = 5.42 N

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