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3 years ago

Mention the importance of writing the number in scientific notation

Physics

1 answer:

Kamila [148]3 years ago

5 0

<h2>Answer:</h2>

<h3>Scientific Notation was developed in order to easily represent numbers that are either very large or very small. ... As you can see, it could get tedious writing out those numbers repeatedly. So, a system was developed to help represent these numbers in a way that was easy to read and understand: Scientific Notation.</h3>

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Consider a block of mass m at rest on an inclined plane of angle theta. An acrobat of mass m_A is standing on the top corner of

shtirl [24]

Answer:

μ = tan θ

Explanation:

For this exercise let's use the translational equilibrium condition.

Let's set a datum with the x axis parallel to the plane and the y axis perpendicular to the plane.

Let's break down the weight of the block

sin θ = Wₓ / W

cos θ = W_y / W

Wₓ = W sin θ

W_y = W cos θ

The acrobat is vertically so his weight decomposition is

sin θ = = wₐₓ / wₐ

cos θ = wₐ_y / wₐ

wₐₓ = wₐ sin θ

wₐ_y = wₐ cos θ

let's write the equilibrium equations

Y axis

N- W_y - wₐ_y = 0

N = W cos θ + wₐ cos θ

X axis

Wₓ + wₐ_x - fr = 0

fr = W sin θ + wₐ sin θ

the friction force has the formula

fr = μ N

fr = μ (W cos θ + wₐ cos θ)

we substitute

μ (Mg cos θ + mg cos θ) = Mgsin θ + mg sin θ

μ = $\frac{(M +m) \ sin \ \theta }{(M +m) \ cos \ \theta }$

μ = tan θ

this is the minimum value of the coefficient of static friction for which the system is in equilibrium.

8 0

3 years ago

"An alpha particle (He2+) with a velocity of 2.6x106m/scrosses a uniform magnetic field at an angle of 37.0°to the field lines a

sergey [27]

Answer:

B = 5.59x10⁹ T

Explanation:

The magnetic force (F), on a the alpha particle with charge (q) that is moving at velocity (v) as the cross product of the velocity and magnetic field (B) is:

$F = qvBsin(\theta)$

F = 1.4x10⁻³ N

v = 2.6x10⁶ m/s

θ = 37.0°

q = 2*p = 2*1.6x10⁻¹⁹ C

Hence, the strength of the magnetic field is:

$B = \frac{F}{qvsin(\theta)} = \frac{1.4 \cdot 10^{-3}}{1.6 \cdot 10^{-19} C*2.6 \cdot 10^{6}*sin(37)} = 5.59 \cdot 10^{9} T$

Therefore, the strength of the magnetic field is 5.59x10⁹ T.

I hope it helps you!

7 0

3 years ago

If an element has 7 electrons how many of them will be in the 2nd energy level

inna [77]

Well first you can not go to the 2nd energy level without the first so the first takes up 2 electrons leaving you 5 electrons and the recommended amount is 8 electrons so you would have 5 electrons left

8 0

4 years ago

Read 2 more answers

Calculate the electric field at the center of a square

pantera1 [17]

Answer:

$E_y=1175510.2\ N.C^{-1}$

The Magnitude of electric field is in the upward direction as shown directly towards the charge $q_1$ .

Explanation:

Given:

side of a square, $a=52.5\ cm$

charge on one corner of the square, $q_1=+45\times 10^{-6}\ C$

charge on the remaining 3 corners of the square, $q_2=q_3=q_4=-27\times 10^{-6}\ C$

<u>Distance of the center from each corners</u> $=\frac{1}{2} \times diagonals$

$diagonal=\sqrt{52.5^2+52.5^2}$

$diagonal=74.25\cm=0.7425\ m$

∴Distance of center from corners, $b=0.3712\ m$

Now, electric field due to charges is given as:

$E=\frac{1}{4\pi\epsilon_0}\times \frac{q}{b^2}$

<u>For charge $q_1$ we have the field lines emerging out of the charge since it is positively charged:</u>

$E_1=9\times 10^9\times \frac{45\times 10^{-6}}{0.3712^2}$

$E_1=2938775.5\ N.C^{-1}$

<u>Force by each of the charges at the remaining corners:</u>

$E_2=E_3=E_4=9\times 10^9\times \frac{27\times 10^{-6}}{0.3712^2}$

$E_2=E_3=E_4=1763265.3\ N.C^{-1}$

<u> Now, net electric field in the vertical direction:</u>

$E_y=E_1-E_4$

$E_y=1175510.2\ N.C^{-1}$

<u>Now, net electric field in the horizontal direction:</u>

$E_y=E_2-E_3$

$E_y=0\ N.C^{-1}$

So the Magnitude of electric field is in the upward direction as shown directly towards the charge $q_1$ .

8 0

3 years ago

An airplane traveling from San Francisco northeast to Chicago travels 1260 km in 3.5 h. What is the airplanes average velocity?

IrinaK [193]

Answer:

Average velocity = 360km/h due Northeast.

Explanation:

Given the following data;

Distance = 1260km

Time = 3.5h.

Velocity =?

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

$Velocity = \frac{distance}{time}$