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Sedaia [141]
3 years ago
9

A section at the top of the page that makes it easy for the recipient to respond to a letter is called a(n

Computers and Technology
1 answer:
Umnica [9.8K]3 years ago
7 0

Answer:

Address block.

Explanation:

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When you're working with a word processing document and you press the del key, what happens?
Svetach [21]

The <DEL> or <Delete> key makes the first character AFTER the cursor
disappear, and everything after it then moves back one space to close up
the hole.

Example: 

If I have this in my document ...                          Most trees are green.

And my cursor is after the 'a', like this:                Most trees a|re green.

Now, if I hit the <delete> key, it deletes the
'r' after the cursor, and the hole closes up,
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5 0
3 years ago
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If an occupation is projected to decline by 7% over the next 10 years, how would you rate the job outlook?
Helen [10]
Steady sounds like the best answer but that’s tough
5 0
3 years ago
What is the output of doublec= 12.0 / 5 Systemoutprintln (c)
artcher [175]

Answer:

The code will produce:-

2.4

Explanation:

In this code the result of the arithmetic operation is stored in the variable c.On evaluating the expression it divides 12.0 by 5 which results in 2.4 and it is stored in float variable c.Then it is printed on the screen using print statement.Since the c is double variable so the result will be a decimal number.

Hence the answer is 4.

6 0
3 years ago
When using bits to represent fractions of a number, can you make all possible fractions?
saw5 [17]
This is your perfect answer

8 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
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