Answer:
second one is correct that is right
Answer:
both charges will have different potential energies that will depend upon the charge magnitude.
Explanation:
It is given that both the charges are on the same equipotential line which means the potential V at which the two charges are is same.
Now the potential energy of a charge at potential V is given by
q×V where q is the charge value
Thus Higher the charge value for a given value of potential , higher will be the potential energy
Thus the larger charge will have higher potential energy and not the same.
Answer:
Resultant displacement = 38.58 miles at an angle of 23.57° north of west.
Explanation:
Let north represent positive y direction and east represent positive x direction. Unit vector along x direction is represented by i and vector along unit vector along y direction is represented by j
Initial displacement = 17 miles north = 17 j miles
Final displacement = 24 miles at an angle of 40° west of north = 24 miles at an angle of 130° to positive x -axis
= (24 cos 130 i + 24 sin 130 j )
= (-15.43 i + 18.36 j ) miles
Total displacement = 17 j + (-15.43 i + 18.36 j) = -15.43 i + 35.36 j
Magnitude of displacement 
Angle to positive x -axis = tan⁻¹(35.36/-15.43) = 113.57°
Resultant displacement = 38.58 miles at an angle of 23.57° west of north.
Answer: 39.5 N
Explanation:
2 x force x static friction coefficient = weight (weight=2μsF)
force = ?
static friction coefficient = 0.416
weight = 32.9N
substituting the values above into the equation we get
2 x F x 0.416 = 32.9
F = 32.9 / (2 x 0.416)
F = 39.5N
Answer:
The number is 
Explanation:
From the question we are told that
The net charge is 
Generally the charge on a electron is 
Generally the number of excess electrons is mathematically represented as

=> 
=> 