Answer:
The number of atoms are
.
Explanation:
Given that,
Diameter 

Distance = 2.60 cm
We calculate the number of atoms
Using formula of numbers of atoms


Hence, The number of atoms are
.
Answer:
15.4 kg.
Explanation:
From the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m').................... Equation 1
Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, V = common velocity of both sphere.
Given: m = 7.7 kg, u' = 0 m/s (at rest)
Let: u = x m/s, and V = 1/3x m/s
Substitute into equation 1
7.7(x)+m'(0) = 1/3x(7.7+m')
7.7x = 1/3x(7.7+m')
7.7 = 1/3(7.7+m')
23.1 = 7.7+m'
m' = 23.1-7.7
m' = 15.4 kg.
Hence the mass of the second sphere = 15.4 kg
Answer:0 N
Explanation:
Because they cancel each other out
The answer is A. Pain Relievers
Answer:
6.04788 in

78.38779 m/s
0.88159 kg
34.55294 J
Explanation:
Circumference is given by

Diameter is given by
The diameter is 6.04788 in

Volume of sphere is given by
The volume is 

Fall velocity is given by
The velocity of the fall will be 78.38779 m/s
Mass is given by


The mass is 0.88159 kg
Kinetic energy is given by

The kinetic energy is 34.55294 J