(10 waves) / (5 sec)
= (10/5) (wave/sec)
= 2 per sec
= 2 Hz .
Answer:
The net acceleration of the boat is approximately 6.12 m/s² downwards
Explanation:
The buoyant or lifting force applied to the boat = 790 N
The mass of the boat lifted by the buoyant force = 214 kg
The force applied to a body is defined as the product of the mass and the acceleration of the body. Therefore, the buoyant force, F, acting on the boat can be presented as follows;
Fₐ = F - W
The weight of the boat = 214 × 9.81 = 2099.34 N
Therefore;
Fₐ = 790 - 2099.34 = -1309.34 N
Fₐ = Mass of the boat × The acceleration of the boat
Given that the buoyant force, Fₐ, is the net force acting on the boat, we have;
F = Mass of the boat × The net acceleration of the boat
F = -1309.34 N = 214 kg × The net acceleration of the boat
∴ The net acceleration of the boat = -1309.34 N/(214 kg) ≈ -6.12 m/s²
The net acceleration of the boat ≈ 6.12 m/s² downwards
Placebos are an important part of clinical studies as they provide researchers with a comparison point for new therapies, so they can prove they are safe and effective. They can provide them with the evidence required to apply to regulatory bodies for approval of a new drug.
Answer:735.46N, 626.34N
Explanation: when an elevator ascend, it means it moving against gravity
F= m(a+g)
M=66kg
a=v/t
g=9.81m/s^2
For the first a= 1.2/0.9
a=1.2/0.9
a=1.33m/s2
F=66(1.33+9.81)
F=66(11.143)
F=735.46N
F=m(a+g)
a=v/t
a=-1.6/5
a=-0.32m/s2
F=66(-0.32+9.8)
F=66(9.49)
F=626.34N
