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4 years ago

Helpppppppp please !!!!

Physics

1 answer:

agasfer [191]4 years ago

7 0

Answer:

second one is correct that is right

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A car is moving at a initial velocity of 20 meters per second accelerates at a rate of 1.5 meters per second squared for 4 secon

Brrunno [24]

Answered using calculus.
Antidifferentiated the acceleration to get velocity. Added variable c as we do not know if there was an extra number there yet.
Knowing that when time is 0, the velocity is 20, we can substitute those numbers into the equation and find that c = 20.
Now we have full velocity equation: v = 1.5t + 20
Now we substitute 4 into t to find out the velocity after 4 seconds. This gives us the final answer of 26m/s

5 0

3 years ago

what is the least efficient way to roast a marshmallow using heat transfer conduction, convection, or radiation?

Kisachek [45]

Answer:

convection

Explanation:

The only way convection can only take place in liquids and gas.Since the marshmello is neither,convection is the least effective way

3 0

3 years ago

The truck now weighs 147,000 N what is the new mass of the truck

katrin [286]

Answer:

14700kg

Explanation:

If you divide it by 10

6 0

3 years ago

An electron travels at a speed of 16,748.76 m/s through a uniform magnetic field whose magnitude is 0.0177 T. What is the magnit

MAVERICK [17]

Answer:

Magnetic force, $F=4.07\times 10^{-17}\ N$

Explanation:

It is given that,

Speed of electron, v = 16748.76 m/s

Magnetic field, B = 0.0177 T

Angle between velocity vector and the magnetic field vector are make an angle of 59.24°. Magnetic force is given by :

$F=qvB\ sin\theta$

$F=1.6\times 10^{-19}\times 16748.76\times 0.0177 \ sin(59.24)$

$F=4.07\times 10^{-17}\ N$

So, the magnetic force on the electron is $4.07\times 10^{-17}\ N$ . Hence, this is the required solution.

7 0

3 years ago

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diame

dalvyx [7]

Complete question:

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball?

Answer:

The acceleration of the ball is 78.98 m/s², directed inwards

Explanation:

Given;

mass of the ball, m = 175 g

radius of the circle, r = 0.5 m

angular speed of the ball, ω = 2 rev/s

The magnitude of the centripetal acceleration of the ball is calculated as follows;

$a_c = \omega^2 r\\\\where;\\\omega \ is \ angular \ speed \ in \ rad/s\\\\a_c = (2\ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} )^2 \times (0.5 \ m)\\\\a_c =78.98 \ m/s^2$

The centripetal acceleration is directed inwards.

8 0

3 years ago