Answer is: Kw of pure water at 50.0°C is <span>5.50 × 10-14</span><span>.
pH = 6.630.
pH = -log</span>[H⁺].
[H⁺] = 10∧(-pH).
[H⁺] = 10∧(-6.63) = 2.34·10⁻⁷ M.
[H⁺] · [OH⁻] = x.
Kw = ?.<span>
Kw = [H</span>⁺] · [OH⁻]. <span>
Kw = x².
Kw = (</span>2.34·10⁻⁷ M)².
Kw = 5.50·10⁻¹⁴ M².
Kw is ionic product of water.
This I believe would be double covalent bonds
Answer:
Anuclear power plant is used to generate electricity
Here's my best guess
the volume of the unit cell is (385*10^-12)^3=5.7066*10^-29 m^3
multiply by density to get mass
mass = (7 g/cm^3)*(100^3 cm^3 / 1^3 m^3) * 5.7066*10^-29 m^3= 3.99466*10^-22 g
covert to moles
3.99466*10^-22 g * 1 mol / 239.82 g = 1.6657 *10^-24 mol
convert to number of units
1.6657 *10^-24 mol * 6.23*10^23 units/mol = 1.04
385 pm = 3.85*10^(-8) cm
The volume of the unit cell is the cube of that, which is 5.71*10^(-23) cm^3. Since the ratio of mass to volume (i.e. the density) must be the same no matter what amount of TlCl you have, you can say:
7 = x/(5.71*10^(-23)), where x is the mass of the unit cell. Solving for x, you get 4*10^(-22) g.
The mass of a molecule of TlCl is 240 amu, which in grams is 4*10^(-22) g. The mass of the unit cell and the mass of a molecule of TlCl is the same. Therefore there is one formula unit of TlCl per unit cell.
The ideal gas law is PV= nRT.
First you need to manipulate the equation to splice for volume,
Which will be V= nRT/P
Now you need to input the numbers for each variable. Make sure to remember what the value R equals and it’s units. R= 0.08206 L•atm/n•K
