Given the atomic mass of select elements, calculate the molar mass of each salt.
1 answer:
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Answer:
Less than the concentration of Pb2+(aq) in the solution in part ( a )
Explanation:
From the question:
A)
We assume that s to be the solubility of PbI₂.
The equation of the reaction is given as :
PbI₂(s) ⇌ Pb²⁺(aq) + 2I⁻(aq); Ksp = 7 × 10⁻⁹
[Pb²⁺] = s
Then [I⁻] = 2s
B)
The Concentration of Pb²⁺ in water is calculated as :
The Concentration of Pb²⁺ in 1.0 mol·L⁻¹ NaI
The equilibrium constant:
It is now clear that maximum possible concentration of Pb²⁺ in the solution is less than that in the solution in part (A). This happens due to the common ion effect. The added iodide ion forces the position of equilibrium to shift to the left, reducing the concentration of Pb²⁺.
Explanation:
It is given that vapor pressure of pure water at 296 K is 2778.5 Pa.These vapors will result in the formation of an ideal gas.
Now, as water is covered with oil and contains only 1% molecules of water. Hence, the vapor pressure of this mixture will also be equal to the vapor pressure of pure water.
So, vapor pressure of mixture = 1% vapor pressure of pure water
Therefore, =
= 27.785 Pa
Thus, we can conclude that the equilibrium vapor pressure of water above the oil layer is 27.785 Pa.
Answer:
Therefore, the rate of change in the amount of salt is
Explanation:
Given:
Initial volume of water lit
Flowing rate = 5
The rate of change in the amount of salt is given by,
( Rate of salt enters tank - rate of sat leaves tank )
Since tank is initially filled with water so we write that,
Let amount of salt in the solution is ,
Therefore, the rate of change in the amount of salt is