Question

Write the equilibrium constant formula for the following reaction: 2H2+O2 yields 2H2O

Answer 1

$2 H_{2} + O_{2} ---\ \textgreater \ 2H_{2}O$

$K= \frac{ [H_{2}O]^{2} }{ [H_{2}]^{2} [O_{2}]}$

Answer 2

Answer:

The expression for an equilibrium constant for the given reaction:

$K_c=\frac{[H_2O]^2}{[H_2]^2[O_2}}$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

$2H_2+O_2\rightleftharpoons 2H_2O$

The expression for an equilibrium constant will be given by:

$K_c=\frac{[H_2O]^2}{[H_2]^2[O_2}}$