Hello there!
To determine the fraction of the hydrogen atom's mass that is in the nucleus, we have to keep in mind that
a Hydrogen atom has 1 proton and 1 electron.
Protons are in the nucleus while electrons are in electron shells surrounding the nucleus.
The mass of the nucleus will be equal to the mass of 1 proton and we can express the fraction as follows:
So, the fraction of the hydrogen atom's mass that is in the nucleus is
0,9995. That means that almost all the mass of this atom is at the nucleus.
Have a nice day!
Answer:
The new pressure is 53.3 kPa
Explanation:
This problem can be solved by this law. when the volume remains constant, pressure changes directly proportional as the Aboslute T° is modified.
T° increase → Pressure increase
T° decrease → Pressure decrease
In this case, temperature was really decreased. So the pressure must be lower.
P₁ / T₁ = P₂ / T₂
80 kPa / 300K = P₂/200K
(80 kPa / 300K) . 200 K = P₂ → 53.3 kPa
Fatty acids are composed of hydrocarbon chains and a carboxyl group.
<h3>What are Fatty acids ?</h3>
Fatty acids are the building blocks of the fat in our bodies and in the food we eat.
During digestion, the body breaks down fats into fatty acids, which can then be absorbed into the blood.
Fatty acid molecules are usually joined together in groups of three, forming a molecule called a triglyceride.
Generally, a fatty acid consists of a straight chain of an even number of carbon atoms, with hydrogen atoms along the length of the chain and at one end of the chain and a carboxyl group (―COOH) at the other end.
It is that carboxyl group that makes it an acid (carboxylic acid).
Learn more about Fatty Acids here ;
brainly.com/question/13528495
#SPJ1
In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not. However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed. The distinction between physical and chemical change is not clear cut.
Answer:
Explanation:
1. The reaction will proceed backward, shifting the equilibrium position to the left.
2. The reaction will proceed forward, shifting the equilibrium position to the right.
3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)
