Answer:
1640 kJ are involved in the reaction
Explanation:
In the reaction:
B₂H₆(g) + 6Cl₂(g) → 2 BCl₃(g) + 6HCl(g)
<em>1 mol of B₂H₆(g) with 6 moles of Cl₂(g) produce 1396 kJ of energy.</em>
<em />
Now if 32.5g of B₂H₆(g) react with excess Cl₂(g), moles involved in reaction are:

If 1 mol produce 1396kJ of energy, 1.175 moles produce:

Thus, <em>1640 kJ are involved in the reaction</em>
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