3 years ago

Can you find the net force of one vertical force and one horizontal force, such as in the picture below? Yes or no, and why?

Physics

2 answers:

den301095 [7]3 years ago

5 0

Answer:

jwuwhisbuebeu said that good morning and private s the

iVinArrow [24]3 years ago

5 0

Answer:

the answer to this question is a⁵/c²

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Mechanics: design a decision tree to determine if an object is experiencing an unbalanced force, and using newton's laws of moti

masya89 [10]

Answer:

The decision designer is a step-wise process

Explanation:

A typical decision tree will be like this:

Are there any forces?

YES - then calculate the resultant forces NO - Then no calculations are needed

IF YES - Are the forces balanced? NO - Then no calculations

IF YES - Then calculations can be done.

Resolve the forces to find the resultant of the forces in the question.

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4 years ago

A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the bal

nikklg [1K]

Given:
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.

By definition, the impulse is
$I = \int_{0}^{2} F(t) dt = \int _{0}^{2} 39dt = 39*2=78 \, N-s$

Answer: 78 N-s

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3 years ago

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Which statement does not describe the relationship between genes and

jek_recluse [69]

Answer: C. Inherited traits carry the instructions for individual genes.

Explanation: bejewels I know stuff. ☆ - ~ hope this helps

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3 years ago

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What is the kinetic energy of a baseball moving at a speed of 40 m/s if the baseball has mass of 0.15 kg?

bonufazy [111]

0.5mv^2 > 0.5*0.15*40*40=120J

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3 years ago

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A man 2 m tall walks horizontally at a constant rate of 1 m/s toward the base of a tower 23 m tall. When the man is 10 m from th

Evgen [1.6K]

Answer:

$\dfrac{d\theta}{dt}=0.038\ rad/s$

Explanation:

Given that

$\dfrac{dx}{dt}= -1\ m/s$

From the diagram

$tan\theta=\dfrac{21}{x}$

By differentiating with time t

$sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}$

When x= 10 m

$tan\theta=\dfrac{21}{10}$

θ = 64.53°

Now by putting the value in equation

$sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}$

$sec^264.53^{\circ} \dfrac{d\theta}{dt}=-\dfrac{21}{10^2}\times (-1)$

$\dfrac{d\theta}{dt}=0.038\ rad/s$

Therefore rate of change in the angle is 0.038\ rad/s

8 0

3 years ago