Answer:
1). Average speed = 1.5 m per second
2). Average velocity = 1.5 m per second
Explanation:
1). Since, speed is a scalar quantity
Therefore, average speed of the trip = ![\frac{\text{Total distance covered}}{\text{Total time taken}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BTotal%20distance%20covered%7D%7D%7B%5Ctext%7BTotal%20time%20taken%7D%7D)
From the graph attached,
Total distance covered = 10 + 10 + 20 + 0 + 20 + 30
= 90 meters
Total time taken = 60 seconds
Average speed = ![\frac{90}{60}](https://tex.z-dn.net/?f=%5Cfrac%7B90%7D%7B60%7D)
= 1.5 meter per second
2). Velocity is a vector quantity.
Therefore, average velocity = ![\frac{\triangle d}{\triangle t}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctriangle%20d%7D%7B%5Ctriangle%20t%7D)
= ![\frac{d_{60}-d_0}{60-0}](https://tex.z-dn.net/?f=%5Cfrac%7Bd_%7B60%7D-d_0%7D%7B60-0%7D)
= ![\frac{90-0}{60-0}](https://tex.z-dn.net/?f=%5Cfrac%7B90-0%7D%7B60-0%7D)
= 1.5 meter per second
Answer:
2.2 s
Explanation:
Using the equation for the period of a physical pendulum, T = 2π√(I/mgh) where I = moment of inertia of leg about perpendicular axis at one point = mL²/3 where m = mass of man = 67 kg and L = height of man = 1.83 m, g = acceleration due to gravity = 9.8 m/s² and h = distance of leg from center of gravity of man = L/2 (center of gravity of a cylinder)
So, T = 2π√(I/mgh)
T = 2π√(mL²/3 /mgL/2)
T = 2π√(2L/3g)
substituting the values of the variables into the equation, we have
T = 2π√(2L/3g)
T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))
T = 2π√(3.66 m/(29.4 m/s² ))
T = 2π√(0.1245 s² ))
T = 2π(0.353 s)
T = 2.22 s
T ≅ 2.2 s
So, the period of the man's leg is 2.2 s
Answer:
In a third class lever, the effort is located between the load and the fulcrum. ... If the fulcrum is closer to the effort, then the load will move a greater distance. A pair of tweezers, swinging a baseball bat or using your arm to lift something are examples of third class levers.
Explanation:
8 phases. I really hope you get the right answer!