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Arisa [49]
3 years ago
11

A 73.0 kg firefighter climbs a flight of stairs 9.0 m high. how much work is required? j

Physics
1 answer:
pshichka [43]3 years ago
7 0
The strength of the fireman in vertical direction will be given by F = m * g. Then, the work done will be given by definition by W = F * d. Substituting the expression of the Force in that of the work, we have that the work will be W = m * g * d. Substituting the given values and assuming that g = 10m / s ^ 2, we have a total work of W = (73) * (10) * (9) = 6570 J
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A 0.15 kg baseball is pushed with 100 N force. what will its acceleration be?
sammy [17]

Answer:

The acceleration of the ball is 666.67 m/s²

Explanation:

It is given that,

Mass of the baseball, m = 0.15 kg

Applied force to it, F = 100 N

We need to find the acceleration of the ball. It can be calculated using Newton's second law of motion as :

F = ma

a=\dfrac{F}{m}

a=\dfrac{100\ N}{0.15\ kg}

a=666.67\ m/s^2

So, the acceleration of the ball is 666.67 m/s². Hence, this is the required solution.

8 0
3 years ago
A 50kg box is pulled on by a rope. The rope applies a horizontal force of 180 N to the box. What is the normal force exerted on
Over [174]
The normal force would be the opposing and equal force to gravity ...  that is why the box isn't floating or going through the ground ... this is Newton's third law of motion

 
4 0
3 years ago
Two identical circular, wire loops 35.0 cm in diameter each carry a current of 2.80 A in the same direction. These loops are par
defon

Answer:

The answer is "4659.2 \times 10^{-24} \ N"

Explanation:

The magnetic field at ehe mid point of the coils is,

\to B=\frac{\mu_0 i R^2}{(R^2+x^2)^{\frac{3}{2}}}\\\\

Here, i is the current through the loop, R is the radius of the loop and x is the distance of the midpoint from the loop.

\to B=\frac{(4\pi\times 10^{-7})(2.80\ A) (\frac{0.35}{2})^2}{( (\frac{0.35}{2})^2+ (\frac{0.24}{2})^2)^{\frac{3}{2}}}\\\\

       =\frac{(12.56 \times 10^{-7})(2.80\ A) \times 0.030625}{( 0.030625+ 0.0144)^{\frac{3}{2}}}\\\\=\frac{  1.07702 \times 10^{-7} }{0.0095538976}\\\\=112.730955 \times 10^{-7}\\\\=1.12\times 10^{-5}\ \ T\\

Calculating the force experienced through the protons:

F=qvB=(1.6 \times 10^{-19}) (2600)(1.12 \times 10^{-5})= 4659.2 \times 10^{-24}\ N

7 0
3 years ago
Why are people so rude???
DanielleElmas [232]

Answer:

I.D.K but the same measure they use to judge will be used to judge them

Explanation:

6 0
2 years ago
Read 2 more answers
What property of light is suggested by the formation of shadows​
Mandarinka [93]

Answer:

The reflection and rectilinear propagation of light helps in the formation of shadows and also tells light doesn't penetrate opaque materials.

3 0
2 years ago
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