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3 years ago

Which expression is equivalent to x + y + x + y + 3 [y + 5]

Mathematics

1 answer:

Alecsey [184]3 years ago

4 0

Answer:

2x +5(y+3)

Step-by-step explanation:

this depends on what you want

x+y+x+y+3(y+5)

expanding this, we have;

2x +2y +3y+15

2x +5y +15

2x +5(y+3)

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Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

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3 years ago

Which equation is an equation of a circle with radius of 10 cm and center at (-3, 6)?

Musya8 [376]

The equation for a circle is
(x-h)^2 + (y-k)^2 = r^2
(-3,6)
-3 is h
6 is k

(x+3)^2 + (y-6)^2 = 10^2
10^2 = 100

(x+3)^2 + (y-6)^2 =100
The answer is B!

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3 years ago

Someone text me on sc queenalyssa_05

tekilochka [14]

Okay! You’re a girl right? Lol

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3 years ago

Find the equation of a line that passes through the point (-2,1) and has a gradient of -3.

zavuch27 [327]

A straight line passing through the point (-2,1) and having a gradient of -3 yields the equation y = -3x - 5.

We know that a straight line is an infinitely long line with no curves on it. A straight line's equation is

y = mx + c...(1), where m is the gradient of the straight line and c is a constant.

Given that the gradient of the given straight line = m = -3.

Putting this value in (1), we get

y = -3x + c ...(2)

Again, the given straight line passes through the point (-2,1). So, we can put x = -2 and y = 1 to get the value of the constant c.

So, 1 = (-3)(-2) + c

i.e. 6 + c = 1

i.e. c = 1 - 6 = -5

(2) can be written as

y = -3x - 5

Therefore the equation of the given straight line is

y = -3x - 5

Know more about straight lines here -

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2 years ago

Can anyone help me? I am having trouble figuring it out.

zimovet [89]

It’s 38.67 because you have to use the formula square root and find the base which is B so you have to do hypotenuse reverse

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3 years ago