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postnew [5]
3 years ago
14

Please help. This is a question on my final exam.

Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0
The best option here is option B.
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5081 divided by 203, the quotient is? Siusjsia
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The quotient is 25.0295566502.

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if a pharmacy technician makes as error resulting in serious consequences who can be held liable in court for error of negligenc
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The very pharmacy technician must be held guilty


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6000 divided by 30 simplified what is it
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Given 4x - y = 32, find:<br> a.) x-intercept<br> b.) y-intercept<br> c.) slope
Rashid [163]
You always want to get y by itself and in the form y = mx + b. So first, subtract 4x from both sides to get -y = -4x +32
You also want to get rid of that negative sign. That’s easy, divide everything by negative 1 to get:
y = 4x - 32

We can see the slope is just 4 and the y intercept is -32. The y-intercept is when x equals zero, you’ll get -32 if you do so. The x-intercept is now when y equals zero. Now solve for x. You get 4x = 32, divide by 4 to get 8

a.) 8
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8 0
3 years ago
State the horizontal asymptote of the rational function. f(x) = quantity x squared plus three x minus two divided by quantity x
omeli [17]

f(x)=\dfrac{x^2+3x-2}{x-2}\\ D_f=\mathbb{R}\setminus\{2\}\\\\ \displaystyle \lim_{x\to \infty}\dfrac{x^2+3x-2}{x-2}=\lim_{x\to \infty}\dfrac{x\left(x+3-\dfrac{2}{x}\right)}{x\left(1-\dfrac{2}{x}\right)}=\lim_{x\to \infty}\dfrac{x+3-\dfrac{2}{x}}{1-\dfrac{2}{x}}=\dfrac{\infty}{1}=\infty\\ \lim_{x\to -\infty}\dfrac{x^2+3x-2}{x-2}=\lim_{x\to -\infty}\dfrac{x\left(x+3-\dfrac{2}{x}\right)}{x\left(1-\dfrac{2}{x}\right)}=\lim_{x\to -\infty}\dfrac{x+3-\dfrac{2}{x}}{1-\dfrac{2}{x}}=\dfrac{-\infty}{1}=-\infty

The limits are not numbers, so the asymptote doesn't exist.

8 0
3 years ago
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