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3 years ago

Why are marine mammals so important

Chemistry

2 answers:

sergejj [24]3 years ago

5 0

Because they help regulate the marine environment.

Nina [5.8K]3 years ago

4 0

what he said.....................srry need points

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What product is released into Earth's atmosphere through the combustion of<br> fossil fuels?

mezya [45]

Answer:

Carbon Monoxide

Explanation:

Fossil fuels are hydrocarbons which only contain hydrogen and carbon.

When it is burnt in air, it reacts according to this general equation:

2(CH) + 3O2 >> H2O + CO + CO2

Carbondioxide
Carbon Monoxide
Water

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1 year ago

Water is added to liquid isopropanol (a polar liquid) to form a solution of rubbing alcohol. Describe what happens on the molecu

olya-2409 [2.1K]

Explanation:

Since liquid isopropanol is a polar liquid and water is also a polar solvent. So, when both of them are added together then according to the like dissolves like principle they get dissolved.

At the molecular level, the polar molecules of isopropanol get attracted towards the polar molecules of water at the surface of water.

As a result, water molecules get surrounded by isopropanol. Thus, water molecules enter the solution and evenly spread into the solution.

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3 years ago

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3 years ago

Ignoring sign which transition is associated with the greatest energy change?

scoray [572]

Well u said ignoring not me

3 0

3 years ago

A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of

Stella [2.4K]

Answer:

See explanation.

Explanation:

Hello,

In this case, we can show how the empirical formula is found by following the shown below procedure:

1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:

$n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC$

2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:

$n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH$

3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:

$m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH} =0.1900gO$

4. Compute the moles of oxygen by using its molar mass:

$n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO$

5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:

$C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1$

6. Search for the closest whole number (in this case multiply by 2):

$C_3H_6O_2$

Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:

$M=12*3+1*6+16*2=74g/mol$

Which is about three times in the molecular formula, for that reason, the actual formula is:

$C_9H_{18}O_6$

It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.

Best regards.

6 0

3 years ago