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harina [27]
3 years ago
12

Can someone help me with this please

Mathematics
1 answer:
nordsb [41]3 years ago
6 0

Answer:

Step-by-step explanation:

The wording on this is not the best.  It sounds like the 1 zero has even multiplicity (that's because of where the modifier is). On top of that it has an odd power.  You could try this. y =x*(x^2+1)^2

The problem is not with the power. It gives x^5. The problem is with the multiplicity of the one place where it crosses. (X^2 + 1) does factor, but it gives a complex root. I'm not sure that's allowed. However, it is the best I can do.

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Please help! While mining, Mike found a large metal bar that contained 6 ounces of lead. Mike also determined that the bar was 4
Dima020 [189]

Answer:

15 ounces

Step-by-step explanation:

6/40 = 0.15

0.15 x 100 = 15

15 ounces

7 0
2 years ago
Can anyone do any of these? :[
raketka [301]

Answer:

yes # 7

Step-by-step explanation:

729 times 59049

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Read 2 more answers
A forester studying the effects of fertilization on certain pine forests in the Southeast is interested in estimating the averag
ahrayia [7]

Answer:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(ZStep-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the area of a population, and for this case we know the distribution for X is given by:

X \sim N(M,4)  

Where \mu=M and \sigma=4

We select a a sample of n =4 and since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(Z

8 0
3 years ago
If f(x)=-2x^2+5x-3 and g(x) is the reflection of f(x) across the y-axis, then an equation of g is which of the following
Ymorist [56]

To reflect a function across the y-axis you have to change

x\mapsto -x

So, the function becomes

f(x)=-2x^2+5x-3 \mapsto f(-x)=-2(-x)^2+5(-x)-3=-2x^2-5-3

3 0
3 years ago
Can y’all help me with this and you’ll get 20 points
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The answers to your page the whole book is online with answer key
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