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3 years ago

Six more than a number, n, is less than fourteen. Which inequality represents this relationship?

Mathematics

1 answer:

Yakvenalex [24]3 years ago

6 0

Answer:

6 + n < 14

just in case...

n < 8

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This probability distribution shows the

Darya [45]

Answer:

30/35=85.71%

Step-by-step explanation:

Observations with A,B,C: 30

Total Observations: 35

$\frac{30}{35} =\frac{6}{7} =.8571$

3 0

2 years ago

3 more than the quotient of a number and 8 is 27.

worty [1.4K]

(x/8) + 3 = 27 <===ur equation

6 0

3 years ago

A thin metal plate, located in the xy-plane, has temperature T(x, y) at the point (x, y). Sketch some level curves (isothermals)

Sophie [7]

Answer:

Step-by-step explanation:

Given that:

$T(x,y) = \dfrac{100}{1+x^2+y^2}$

This implies that the level curves of a function(f) of two variables relates with the curves with equation f(x,y) = c

here c is the constant.

$c = \dfrac{100}{1+x^2+2y^2} \ \ \--- (1)$

By cross multiply

$c({1+x^2+2y^2}) = 100$

$1+x^2+2y^2 = \dfrac{100}{c}$

$x^2+2y^2 = \dfrac{100}{c} - 1 \ \ -- (2)$

From (2); let assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.

Now,

$\dfrac{(x)^2}{\dfrac{100}{c}-1 } + \dfrac{(y)^2}{\dfrac{50}{c}-\dfrac{1}{2} }=1$

This is the equation for the family of the eclipses centred at (0,0) is :

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1$

$a^2 = \dfrac{100}{c} -1 \ \ and \ \ b^2 = \dfrac{50}{c}- \dfrac{1}{2}$

Therefore; the level of the curves are all the eclipses with the major axis:

$a = \sqrt{\dfrac{100 }{c}-1}$ and a minor axis $b = \sqrt{\dfrac{50 }{c}-\dfrac{1}{2}}$ which satisfies the values for which 0< c < 100.

The sketch of the level curves can be see in the attached image below.

7 0

3 years ago

11. Lucas is making one dozen sn

anygoal [31]

Answer:

Lucas needs 12 cups of dried cherries and 24 cups of dried apricots to make one dozen of snacks for his team

Step-by-step explanation:

For each snacks Lucas uses one cup of dried cherries and 2 cup of dried apricots. One dozen of snack contains a total of 12 snacks. Therefore to prepare 12 snacks (one dozen) the number of dried cherries and dried apricots can be gotten by multiplying the number of dried cherries and dried apricots required for each snack by 12.

Number of dried cherries = 1 cup for each snack × 12 snacks = 12 cups

Number of dried apricots = 2 cup for each snack × 12 snacks = 24 cups

Lucas needs 12 cups of dried cherries and 24 cups of dried apricots to make one dozen of snacks for his team

3 0

3 years ago

-1 3/7 • (-3 2/3) = ? A: 3 2/7 B: 5 5/21 C: 11 D: -5 5/21

Anna35 [415]

[|] Answer [|]

$\boxed{5 \ \frac{5}{21}}$