Answer:
x = 7
Step-by-step explanation:
recognize that this is a right triangle with one of the internal angles = 45°. This means that the other angle not shown is 180 - 90 - 45 = 45°
This makes the triangle an isosceles triangle.
If so, x must be the same length as the other side adjacent to 90°
i.e x = 7
Answer:
I believe the answer is 90
Step-by-step explanation:
Answer:
given you are asked to simplify
![\frac{-3+5i}{-3-4i}](https://tex.z-dn.net/?f=%5Cfrac%7B-3%2B5i%7D%7B-3-4i%7D)
Step-by-step explanation:
You have to multiply the numerator and denominator by the denominator's conjugate.
The conjugate of a+bi is a-bi.
When you multiply conjugates, you just have to multiply first and last.
(a+bi)(a-bi)
a^2-abi+abi-b^2i^2
a^2+0 -b^2(-1)
a^2+-b^2(-1)
a^2+b^2
See no need to use the whole foil method; the middle terms cancel.
So we are multiplying top and bottom of your fraction by (-3+4i):
![\frac{-3+5i}{-3-4i} \cdot \frac{-3+4i}{-3+4i}=\frac{(-3+5i)(-3-4i)}{(-3-4i)(-3+4i)}](https://tex.z-dn.net/?f=%5Cfrac%7B-3%2B5i%7D%7B-3-4i%7D%20%5Ccdot%20%5Cfrac%7B-3%2B4i%7D%7B-3%2B4i%7D%3D%5Cfrac%7B%28-3%2B5i%29%28-3-4i%29%7D%7B%28-3-4i%29%28-3%2B4i%29%7D)
So you will have to use the complete foil method for the numerator. Let's do that:
(-3+5i)(-3+4i)
First: (-3)(-3)=9
Outer:: (-3)(4i)=-12i
Inner: (5i)(-3)=-15i
Last: (5i)(4i)=20i^2=20(-1)=-20
--------------------------------------------Combine like terms:
9-20-12i-15i
Simplify:
-11-27i
Now the bottom (-3-4i)(-3+4i):
F(OI)L (we are skipping OI)
First:-3(-3)=9
Last: -4i(4i)=-16i^2=-16(-1)=16
---------------------------------------------Combine like terms:
9+16=25
So our answer is ![\frac{-11-27i}{25}{/tex] unless you want to seprate the fraction too:[tex]\frac{-11}{25}+\frac{-27}{25}i](https://tex.z-dn.net/?f=%5Cfrac%7B-11-27i%7D%7B25%7D%7B%2Ftex%5D%20unless%20you%20want%20to%20seprate%20the%20fraction%20too%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cfrac%7B-11%7D%7B25%7D%2B%5Cfrac%7B-27%7D%7B25%7Di)
Answer:
It would be a
Step-by-step explanation:
the difference is 4/8 but simplified it is 1/2
Answer:
9 textbooks!
Step-by-step explanation:
Rucksack can hold = 6kg
Mass of textbook = 680g
So, here we need to show the division for finding the number of textbooks it can hold.
680 g in KG's = 0.68
Now, 6/0.68
That is 8.82 ( Round off = 9 textbooks)