This is actually fun. First comment is brainliest.
2 answers:
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When water at 50 C is added to ice at -12 C, heat is transferred from hot water to ice.
- Heat given out by water = Heat absorbed by ice
Calculating the heat released by hot water:
ΔT
Calculating heat absorbed by 16 g of ice: Ice at is converted to ice at
and then ice at
to water at
ΔT +
+
q = 405.12 J +5336.8 J =5741.92 J
- Heat given out by water = Heat absorbed by ice
-(
m = 27.4 g
Therefore, 27.4 g water at must be added to 16 g of ice at
to convert to liquid water at