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ivanzaharov [21]
3 years ago
7

Complete these structures by adding electron dots as needed.

Chemistry
1 answer:
LiRa [457]3 years ago
7 0
This is hard to show but here is how you would determine these. NOTE each dot is an electron. 
<span>Question 1) </span>
<span>F-H </span>
<span>1) determine the valance electrons for each. F has 7 and H has 1 </span>
<span>2) one electron from both F and H form the bond "-" which means that you still have 6 electrons to place around F and none to place around H. Place the 6 in sets of 2 around the F </span>
<span>.. </span>
<span>F-H </span>
<span>¨ </span>
<span>Question 2) </span>

<span>2) H-O-H </span>
<span>H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place </span>
<span>H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place </span>
<span>O has 6 valence electrons minus 2 used in the bonds to the H's = 4 electrons to place </span>

<span>H-O-H: place two dots above and below the oxygen </span>

<span>Question 3) </span>
<span>3) O=N----H : NOTE: a double bond requires O and N to share two of their electrons each </span>
<span>O has 6 valence electrons minus 2 used in the bonds to N = 4 electrons to place </span>
<span>N has 5 valence electrons minus 3 used in the bonds to O and H = 2 electrons to place </span>
<span>H has 1 valence electron minus 1 used in the bond to N = 0 electrons to place </span>
<span>place the 2 dots on top and bottom of oxygen. </span>
<span>place 2 above the N </span>
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Answer:

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Explanation:

I hope it helps u dear! ^_^

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3 years ago
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Explaination

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swat32

Answer:

\frac{V _{1}}{T _{1}}  =  \frac{V _{2}}{T _{2} }  \\  \frac{446.9}{(14 + 273)}  =  \frac{238.7}{T _{2} } \\ {T _{2}} =  \frac{238.7 \times 287}{446.9}  \\ {T _{2}} = 153.3 \: kelvin \\  = 119.7  \degree \: c

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The value of Ka for phenol (a weak acid), C6H5OH, is 1.00×10-10. Write the equation for the reaction that goes with this equilib
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Answer:

Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}

Explanation:

Hello,

In this case, weak acids are characterized by the fact they do not dissociate completely, it means they do not divide into the conjugated base and acid at all, a percent only, which is quantified via equilibrium. In such a way, the chemical equation representing such incomplete dissociation is said to be:

C_6H_5OH\rightleftharpoons C_6H_5O^-+H^+

Thus, we can write the law of mass action, which consider the equilibrium concentrations of all the involved species, which is also known as the acid dissociation constant which accounts for the capacity the acid has to yield hydronium ions:

K=Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}

Best regards.

3 0
3 years ago
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