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Eddi Din [679]
4 years ago
7

Avogadro's number is equal to​?

Chemistry
2 answers:
Lerok [7]4 years ago
4 0

Answer:

6.273×10²³

Explanation:

hope this is useful friend

Ray Of Light [21]4 years ago
3 0

Answer:

6.023 × 10²³

Explanation:

Avogadro's number is used for calculating masses and moles and can applied to Stoichiometry. Avogadro's number is useful for atoms and molecules

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If water is present during the grignard formation, what possible byproduct may form?
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Important of Grignard Reagent :

Grignard reactions are main due to their capacity to form carbon-carbon bonds. Grignard reagents are powerful bases and will react with protic compounds which makes them exceptionally valuable implement for organic synthesis.

Grignard reagents react fastly with acidic hydrogen atoms in molecules such as alcohols and water. When a Grignard reagent reacts with water, a proton return back halogen, and the product is an alkane. The Grignard reagent therefore provides a trace for transforming a haloalkane to an alkane in two steps.

When reacted with water,

RMgX + H2O -------> R-H + MgOH X

R ---- Alkyl Group

X --- Halogen

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Which of these redox reactions is spontaneous as written?
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Which phrase accurately describes the location of Africa? O mostly in the eastern hemisphere mostly south of the Tropic of Capri
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3 years ago
An unknown gas contains 5.4 moles in 34 mL. If the amount of gas increases to 6.2 moles, what is the new volume?
Murljashka [212]

At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.

<h3>What is Avogadro's law?</h3>

Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

It is expressed as;

V₁/n₁ = V₂/n₂

Given the data in the question;

  • Initial amount of gas n₁ = 5.4moles
  • Initial volume v₁ = 34mL = 0.034L
  • Final amount of gas n₁ = 6.2moles
  • Final volume v₂ = ?

We substitute our values into the expression above.

V₁/n₁ = V₂/n₂

V₁n₂ = V₂n₁

V₂ = V₁n₂ / n₁

V₂ = (0.034L × 6.2moles) / 5.4moles

V₂ = 0.2108molL / 5.4mol

V₂ = 0.039L

V₂ = 39 mL

Therefore, at constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.

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