Answer: 0.67 ml
Explanation:
According to the dilution law,
where,
= concentration of stock solution = 226 mg/ml
= volume of stock solution = ?
= concentration of working solution= 15 mg/ml
= volume of working solution= 10 ml
Putting in the values we get:
Thus volume of stock solution needed to dilute to have 10mL of working solution at the above concentration is 0.67 ml
Mass of Hydrogen gas required to react : 0.936 g
<h3>Further explanation</h3>
Reaction on Nitrogen gas and Hydrogen gas to produce Ammonia gas
N₂ (g) + 3 H₂ (g) ⇒ 2 NH₃ (g)
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol
so mol Nitrogen for 3.5 L at STP :
From the equation, mol ratio of N₂ : H₂ = 1 : 3, so mol H₂ :
then mass of Hydrogen(MW= 2 g/mol) :
The moles of each element found in a 5.00 g nickel coin is calculated as below
moles =mass/molar mass
calculate the mass of each element =% composition of element/100 x total mass of nickel
Mn = 9/100 x5 = 0.45g
Cu=56/100 x5= 2.8 g
Ag= 35/100x5= 1.75 g
moles of each element is therefore=
Mn = 0.45g/54.94 = 8.19 x10^-3 moles
Ag=1.75g/107.87 g/mol = 0.0162 moles
Cu = 2.8 g/63.5 g/mol=0.0441 moles
Hey the answer to your question is Option C
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Answer:
5010J
Explanation:
The following data were obtained from the question:
Mass (m) = 15g
Heat of fusion (ΔHf) = 334J/g
Heat required (Q) =..?
The heat energy required to melt the ice can be obtained as follow:
Q = m·ΔHf
Q = 15 x 334
Q = 5010J
Therefore, the heat energy required to melt the ice is 5010J.
