Answer:
Mass = 12.48 g
Explanation:
Given data:
Mass of sulfur dioxide = 25.0 g
Mass of sulfur formed = ?
Solution:
Chemical equation:
SO₂ → S + O₂
Number of moles of SO₂:
Number of moles = mass/molar mass
Number of moles = 25.0 g / 64.07 g/mol
Number of moles = 0.39 mol
Now we will compare the moles of SO₂ with S.
SO₂ : S
1 : 1
0.39 : 0.39
Mass of sulfur:
Mass = number of moles × molar mass
Mass = 0.39 mol × 32 g/mol
Mass = 12.48 g
They die because theyre aliens
Answer:
B) H2SO4 (aq) + Ca(OH)2 (aq) → CaSO4 (aq) + 2 H2O(l)
Explanation:
A is a reaction between a salt FeCl3 and a base KOH
C is a n acid decomposing on it's own to form two products
D is mercury, a metal reacting with oxygen. Two elements reacting. Neither are an acid or a base
E. is an acid reacting with a metal to liberate hydrogen. There is no base
The 3rd diagram is a mixture because it has 2 substances
Answer:
We need 17.2 L of Ca(OH)2
Explanation:
Step 1: Data given
Concentration of Ca(OH)2 = 1.45 M
Moles of H2SO4 = 25.0 moles
Step 2: The balanced equation
Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4
Step 3: Calculate moles Ca(OH)2
For 1 mol Ca(OH)2 we need 1 mol H2SO4 to produce 2 moles H2O and 1 mol CaSO4
For 25.0 moles H2SO4 we'll need 25.0 moles Ca(OH)2 to produce 50 moles H2O and 25.0 moles CaSO4
Step 4: Calculate volume of Ca(OH)2
Volume Ca(OH)2 = moles Ca(OH)2 / concentration Ca(OH)2
Volume Ca(OH)2 = 25.0 moles / 1.45 M
Volume Ca(OH)2 = 17.2 L
We need 17.2 L of Ca(OH)2
