Ask question

Ask question

All categories

2 years ago

14

What effect does increased blood flow have on the body when performing exercises? A. delivers more sugar to organs B. delivers m

ore energy to muscles C. delivers more oxygen to the body D. delivers more protein to muscles Please select the best answer from the choices provided. O A . OB ос OD Next Submit Save and Exit Mark this and return

1 answer:

denis23 [38]2 years ago

5 0

The answer is C!
Good luck!

You might be interested in

Unlike the idealized voltmeter, a real voltmeter has a resistance that is not infinitely large. part a a voltmeter with resistan

Margaret [11]

The EMF of the battery includes the force to to drive across its internal resistance. the total resistance:
R = internal resistance r + resistance connected rv
R = r + rv
Now find the current:
V 1= IR
I = R / V1
find the voltage at the battery terminal (which is net of internal resistance) using
V 2= IR
So the voltage at the terminal is:
V = V2 - V1
This is the potential difference vmeter measured by the voltmeter.

6 0

3 years ago

Read 2 more answers

Which global concern is indirectly responsible for all of the others? A) pollution B) deforestation C) resource depletion D) hum

vredina [299]

D) human overpopulation

8 0

2 years ago

Read 2 more answers

What is the difference between organic and inorganic material?

babymother [125]

Organic materials comes from living things while inorganic materials comes from non living things

Organic materials are those composed mainly of carbon they are derived from living things while inorganic materials are derived from non living things sucjh as rocks etc

5 0

2 years ago

(4%) Problem 9: A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring

skad [1K]

Answer:

a) Acceleration is zero , c) Speed is cero

Explanation:

a) the equation that governs the simple harmonic motion is

x = A cos (wt +φφ)

Where A is the amplitude of the movement, w is the angular velocity and φ the initial phase determined by the initial condition

Body acceleration is

a = d²x / dt²

Let's look for the derivatives

dx / dt = - A w sin (wt + φ)

a = d²x / dt² = - A w² cos (wt + φ)

In the instant when it is not stretched x = 0

As the spring is released at maximum elongation, φ = 0

0 = A cos wt

Cos wt = 0 wt = π / 2

Acceleration is valid for this angle

a = -A w² cos π/2 = 0

Acceleration is zero

b)

c) When the spring is compressed x = A

Speed is

v = dx / dt

v = - A w sin wt

We look for time

A = A cos wt

cos wt = 1 wt = 0, π

For this time the speedy vouchers

v = -A w sin 0 = 0

Speed is cero

5 0

3 years ago

A 75 kg baseball player runs at a velocity of 6 m/s before sliding to a stop at second base. a. What is the kinetic energy of th

lana [24]

Answer:

a. $\displaystyle k_o=1350\ J$

b. $\displaystyle k_1=0\ J$

c. $\Delta k=-1350\ J$

d. $W=-1350\ J$

e. $F=-675\ N$

Explanation:

<u>Work and Kinetic Energy </u>

When an object moves at a certain velocity v0 and changes it to v1, a change in its kinetic energy is achieved:

$\Delta k=k_1-k_0$

Knowing that

$\displaystyle k=\frac{mv^2}{2}$

We have

$\displaystyle \Delta k=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

The work done by the force who caused the change of velocity (acceleration) is

$\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

If we know the distance x traveled by the object, the work can also be calculated by

$W=F.x$

Being F the force responsible for the change of velocity

The 75 kg baseball player has an initial velocity of 6 m/s, then he slides and stops

a. Before the slide, his initial kinetic energy is

$\displaystyle k_o=\frac{mv_0^2}{2}$

$\displaystyle k_o=\frac{(75)6^2}{2}$

$\boxed{\displaystyle k_o=1350\ J}$

b. Once he reaches the base, the player is at rest, thus his final kinetic energy is

$\displaystyle k_1=\frac{(75)0^2}{2}$

$\boxed{\displaystyle k_1=0\ J}$

c. The change of kinetic energy is

$\Delta k=k_1-k_0=0\ J-1350\ J$

$\boxed{\Delta k=-1350\ J}$

d. The work done by friction to stop the player is

$W=\Delta k=k_1-k_0$

$\boxed{W=-1350\ J}$

e. We compute the force of friction by using

$W=F.x$

and solving for x

$\displaystyle F=\frac{W}{x}$

$\displaystyle F=\frac{-1350\ J}{2\ m}$

$\boxed{F=-675\ N}$

The negative sign indicates the force is against movement

6 0

2 years ago