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gayaneshka [121]
4 years ago
5

if you throw a 0.25 kilogram ball with a force of 20 newtons what's the answer what's the acceleration of ball

Physics
2 answers:
tatyana61 [14]4 years ago
6 0
First calculate the the force per kilogram(0.25 / 20 or 80N) so 80m/s^2 
olga55 [171]4 years ago
4 0
I'll give this a shot. I know someone else has most likely answered this by the time I'm done answering, but it is good to have more than one answer after all.
In physics, force is equal to mass multiplied to acceleration. We are given the info that the mass is 0.25 kg and the force is 20 N. 

F = ma 
20 N = 0.25 kg * a 
20 kg*m/s^2 = 0.25 kg * a 
a = 20/0.25 
a = 80 m/s^2

So the acceleration of the ball is 80 m/s^2. 
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A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.90 kg box that is sitting on the horizontal,
Lady_Fox [76]

Answer:

6.875 m/s

Explanation:

The force is variable which is given by

F(x) = 18 - 0.53 x

mass of the box, m = 8.9 kg

initially it is at rest at x = 0

Let the velocity is v after travelling a distance of 15 m.

According to the work energy theorem, the work done by all the forces is equal to the change in kinetic energy of the body.

Work done = change in kinetic energy

\int \overrightarrow{F}.d\overrightarrow{x}=\Delta  K.E

\int_{0}^{15} \left ( 18-0.53 x \right )dx=\frac{1}{2}\times m \left ( v^{2}-u^{2} \right )

\left ( 18x-0.265x^{2} \right )_{0}^{15}=\frac{1}{2}\times 8.9\times  \left ( v^{2}-0^{2} \right )

18 x 15 - 0.265 x 15 x 15 = 4.45 x v²

270 - 59.625 = 4.45 v²

v² = 47.275

v = 6.875 m/s

Thus, the final velocity of the box is 6.875 m/s.

4 0
3 years ago
A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is
Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration a_{c} is given by the following equation:  

a_{c}=\frac{V^{2}}{r} (1)

Where:  

a_{c}=17 m/s^{2} is the <u>centripetal acceleration</u>

V is the<u> tangential speed</u>

r=12 m is the <u>radius</u> of the circle

Isolating V from (1):

V=\sqrt{a_{c}r} (2)

V=\sqrt{(17 m/s^{2})(12 m)}

<u />

Finally:

V=14.28 m/s This is the girl's tangential speed

3 0
3 years ago
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KengaRu [80]

Answer: A.The total number of energy levels the electron can jump to.

Explanation:

Spectral lines are bright or dark lines over continuous spectrum which occur due to emission or absorption of energy.

When an electron jumps to or from one energy level to another energy level, spectral lines are produced. The range of spectral lines depends on the number of energy levels available to which the electron can jump. This depends the amount of energy gained/lost by the electron.

Thus, the correct answer is: A.The total number of energy levels the electron can jump to.

8 0
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