Answer:
(a) The amount of O2 needed is 2.67 pounds.
(b) The volume required is 847,509 litres.
(c) The heat given off as a result of the combustion to CO2 is 393.5 kJ.
Explanation:
For a complete combustion of C to C02(g)
(a) The molecular mass of O2 is 32 g/mol and the molecular mass of C is 12 g/mol.
We need 1 mol O2 to burn 1 mol of C.
If we need 32 g of O2 to burn 12 g of C, to burn 1 pound of pure carbon charcoal we need (32/12)*1=2.67 pounds of O2.
(b) The density of O2, at atmospheric conditions, is 1.429 g/l. The volume of 2.67 pounds of O2 is
(c) To calculate the heat of the reaction, we have to look up in the Table of Standard Enthalpy of Formation Values and compute the following equation
The heat given off as a result of the combustion to CO2 is 393.5 kJ.
The volume of the cone can be calculated as follows:
volume of cone = (1/3) x pi x (radius)^2 x height .......> equation 1
We know that the height is twice the diameter, therefore:
h = 2d .............> equation 2
we also know know that the radius is half the diameter:
r = (1/2) d
d = 2r ...................> equation 3
Substitute with equation 3 in equation 2, we get:
h = 2d = 2 (2r)
h = 4r
r = (1/4) h................> equation 4
Substitute with equation 4 in equation 1, we get:
volume of cone = (1/3) x pi x (radius)^2 x height
= (1/3) x pi x (0.25 h)^2 x h
= (1/3) x pi x (1/16) h^2 x h
= (1/48) x pi x h^3
Explanation:
Given parameters:
Wavelength of photon = 1.95 x 10⁻¹¹m
Unknown:
Frequency of the wave = ?
Energy of the photon = ?
Solution:
The frequency and wavelength of a wave are related by the expression;
C = Fλ
C = speed of light = 3 x 10⁸m/s
F = frequency
λ = wavelength
Insert the parameters and solve;
3 x 10⁸ = F x 1.95 x 10⁻¹¹
F = = 1.54 x 10¹⁹Hz
Energy of the photon is related to frequency using the expression below;
E = hF
h is the Planck's constant = 6.634 x 10⁻³⁴m²kg/s
Insert the parameters and solve;
E = 6.634 x 10⁻³⁴ x 1.54 x 10¹⁹ = 1.02 x 10⁻¹⁴J
Shii ion even know it’s A