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Dimas [21]
2 years ago
13

Draw the electron configuration for a neutral atom of nitrogen.

Chemistry
1 answer:
velikii [3]2 years ago
6 0

Answer:

1s22s22p3.

Explanation:

Electronic configuration of a neutral atom is 1s22s22p3.  

Please see the image attached

 

Neutral atom of nitrogen will have equal number of proton and electron i.e equal to 7. 7 electron of the nitrogen are placed into the s and p orbitals in the ground state.  

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Can some one plz help
blsea [12.9K]

The reaction uses B) 9.0 g Br₂.

 iron + bromine ⟶ product

2.0 g +     <em>x</em> g     ⟶   11.0 g

According to the <em>Law of Conservation of Mass</em>, the total mass of the reactants must equal the total mass of the products.

∴2.0 + <em>x</em> = 11.0

<em>x</em> = 11.0 – 2.0 = 9.0

The reaction uses 9.0 g Br₂.

5 0
2 years ago
Which element can join with other elements to form covalent bonds? beryllium (Be) carbon (C) cesium (Cs) iron (Fe)
Rainbow [258]

Answer:

Carbon (C)

Explanation:

Carbon is the only nonmetal there and covalent bonds happen between two nonmetal atoms

4 0
3 years ago
Read 2 more answers
Sodium metal reacts with water to produce hydrogen gas.
Darina [25.2K]

Answer:

Explanation:

Question 6 options:

1)

A single replacement reaction takes place because sodium is less reactive than hydroxide ions.

7 0
2 years ago
What is the definition of bond?
JulijaS [17]
Join or be joined securely to something else, typically by means of an adhesive substance, heat, or pressure.
3 0
2 years ago
aseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.5 g of methane is
maksim [4K]

Answer:

There is 9.6 grams of CO2 produced

Explanation:

Step 1: Data given

Mass of methane = 5.50 grams

Molar mass of methane = 16.04 g/mol

Mass of oxygen = 13.9 grams

Molar mass of oxygen = 32.0 g/mol

Step 2: The reaction

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles methane = 5.50 grams / 16.04 g/mol

Moles methane = 0.343 moles

Moles oxygen = 13.9 grams / 32.0 g/mol

Moles oxygen = 0.434 moles

For 1 mol CH4 we need 2 moles O2 to produce 1 mol CO2 and 2 moles H2O

O2 is the limiting reactant. It will completely react (0.434 moles).

There will react 0.434/2 = 0.217 moles CH4

There will remain 0.343-0.217 = 0.126 moles CH4

There will be produced 0.434 moles of H2O and

0.434/2 =0.217 moles of CO2

Step 4: Calculate mass of products

Mass = moles * molar mass

Mass CO2 = 0.217 moles ¨44.01 g/mol

Mass CO2 = 9.6 grams

Mass H2O = 0.434 moles * 18.02

Mass H2O = 7.8 grams

4 0
2 years ago
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