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Juli2301 [7.4K]
3 years ago
11

A flywheel of diameter 1.2 m has a constant angular acceleration of 5.0 rad/s2. The tangential acceleration of a point on its ri

m is:_____.
a. 12 m/s2.
b. 6.0 m/s2.
c. 5.0 m/s2.
d. 5.0 rad/s2.
e. 3.0 m/s2.
Physics
1 answer:
Anna71 [15]3 years ago
3 0

Answer:

3 m/s²

Explanation:.

To solve this, we use the formula of tangential acceleration. The tangential acceleration is given by the following equation:

a(t) = r * a(a)

where

a(t) is the tangential acceleration, m/s²

r is the radius, m

a(a) is the angular acceleration, rad/s²

Again, we know that the radius can be gotten by saying r = d/2, thus, r = 1.2/2 = 0.6 m

We then multiply this by the angular acceleration, to get our tangential acceleration

a(t) = 0.6 * 5 = 3 m/s²

Therefore, the Tangential acceleration of a point on the flywheel rim has been found to be 3 m/s²

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Complete question is;

A single-phase 60-Hz overhead power line is symmetrically supported on a horizontal cross arm. Spacing between the centers of the conductors acing between the centers of the conductors (say, a and b) is 2.5 m. A telephone line is also symmetrically supported on a horizontal cross arm 1.8 m directly below the power line. Spacing between the centers of these conductors (say, c and d) is 1.0 m.

The mutual inductance per unit length between circuit a-b and circuit c-d is given as 4 x 10^(-7) ln √((D_ad × D_bc)/(D_ac × D_bd)) H/m

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a. Hence, compute the mutual inductance per kilometer between the power line and the telephone line.

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Answer:

A) M = 1.01 × 10^(-4) H/km

B) v_cd = 5.712 V/km

Explanation:

A) From the distances given in the question, we can deduce that;

D_ac = √(((2.5/2) - (1/2))² + 1.8²)

D_ac = 1.95 m

Also;

D_ad = √(((2.5/2) + (1/2))² + 1.8²)

D_ad = 2.51 m

I_a and I_b are put of phase by 180°. Thus, due to a and b, the flux linkages to c and d is given as;

φ_cd = 4 x 10^(-7)I_a( ln (2.51/1.95))

Mutual inductance per km is given as;

M = φ_cd/I_a

Thus;

M = 4 x 10^(-7)( ln (2.51/1.95))

M = 1.01 × 10^(-7) H/m

Per km;

M = 1.01 × 10^(-7) × 1000

M = 1.01 × 10^(-4) H/km

B) voltage per km is gotten by;

v_cd = ωMI

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v_cd = 377 × 1.01 × 10^(-4) × 150

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Answer:

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