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Juli2301 [7.4K]
3 years ago
11

A flywheel of diameter 1.2 m has a constant angular acceleration of 5.0 rad/s2. The tangential acceleration of a point on its ri

m is:_____.
a. 12 m/s2.
b. 6.0 m/s2.
c. 5.0 m/s2.
d. 5.0 rad/s2.
e. 3.0 m/s2.
Physics
1 answer:
Anna71 [15]3 years ago
3 0

Answer:

3 m/s²

Explanation:.

To solve this, we use the formula of tangential acceleration. The tangential acceleration is given by the following equation:

a(t) = r * a(a)

where

a(t) is the tangential acceleration, m/s²

r is the radius, m

a(a) is the angular acceleration, rad/s²

Again, we know that the radius can be gotten by saying r = d/2, thus, r = 1.2/2 = 0.6 m

We then multiply this by the angular acceleration, to get our tangential acceleration

a(t) = 0.6 * 5 = 3 m/s²

Therefore, the Tangential acceleration of a point on the flywheel rim has been found to be 3 m/s²

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A loaded 500 kg sled is traveling on smooth horizontal snow at 5 m/s when it suddenly comes to a rough region. The region is 10
sergejj [24]

Answer:

400 N

Explanation:

Change of Kinetic Energy to Friction Wok

∆KE = W

½ x m x (v(5)² - v(3)²) = f x d

½ x 500 x (5² - 3²) = f x 10

250 x (25 - 9) = f x 10

25 x 16 = f

f = 400 N

6 0
3 years ago
A closed box is filled with dry ice at a temperature of -87.1°C, while the outside temperature is 17.6°C. The box is cubical, me
natta225 [31]

Answer:

K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹

Explanation:

Rate of flow of heat through a material is given by the following expression

\frac{Q}{t} =\frac{KA\delta T}{d}

where Q is amount of heat flowing in time t through area A and  a medium of thickness d having two faces at temperature difference δT . K is thermal conductivity of the medium .

Here Q = 3.34 x 10⁶/6 , t = 24 x 60 x 60 = 86400 s , A = .332 X .332 = .0110224 m² ,  δT = 104.7

Put these values here

\frac{3.34\times10^6}{6\times86400}= \frac{k\times.011224\times104.7}{4.41\times10^{-2}}

K=\frac{3.34\times4.41\times10^4}{6\times86400\times.011224\times104.7}

K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹

4 0
3 years ago
Calculate the efficiency of a machine if the input work is 200J and the output work is 150J.​
lidiya [134]

Answer:

75% is the efficency of this maxhine

8 0
3 years ago
A 4800 Watt heater is supposed to be plugged into a 120 volt outlet to work correctly. If the heater was plugged into a 90 volt
dedylja [7]

Answer:

3600

Explanation:

90 of 120 is 3/4 so 4800 - 1200 is 3600.

3 0
3 years ago
A rotating wheel requires 5 s to rotate 38 revolutions. Its angular velocity at end of time interval 5-s is 79 rad/s. What is th
Lera25 [3.4K]

"Rotating wheel" is meant to indcate that the wheel is already rotating at the start. Denote the initial angular velocity by <em>ω₀</em>. Then the angular displacement <em>θ</em> at time <em>t</em> is

<em>θ</em> = <em>ω₀t</em> + 1/2 <em>αt</em> ²

while the angular velocity <em>ω</em> is

<em>ω</em> = <em>ω₀</em> + <em>αt</em>

<em />

It takes 5 s for the wheel to rotate 38 times, or turn a total of (2<em>π</em> rad/rev) (38 rev) = 76<em>π</em> rad, as well as to reach an angular velocity of 79 rad/s, so that

76<em>π</em> rad = <em>ω₀</em> (5 s) + 1/2 <em>α</em> (5 s)²

79 rad/s = <em>ω₀</em> + <em>α</em> (5 s)

Solve the second equation for <em>ω₀</em> and substitute into the first equation, then solve for <em>α</em> :

<em>ω₀</em> = 79 rad/s - <em>α</em> (5 s)

==>   76<em>π</em> rad = (79 rad/s - <em>α</em> (5 s)) (5 s) + 1/2 <em>α</em> (5 s)²

==>   76<em>π</em> rad = (79 rad/s) (5 s) - 1/2 <em>α</em> (5 s)²

==>   1/2 <em>α</em> (5 s)² = (79 rad/s) (5 s) - 76<em>π</em> rad

==>   <em>α</em> = ((79 rad/s) (5 s) - 76<em>π</em> rad) / (1/2 (5 s)²)

==>   <em>α</em> ≈ 12.5 rad/s²

3 0
3 years ago
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