Car X traveled 3d distance in t time. Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t, the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.
In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.

Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.

We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.
156 is the answer. so 156.25 is almost the same thing, you just round. It's not hard. Thank you!!!
"Acceleration" means any change in the speed or direction of motion ... speeding up, slowing down, or turning. So . . .
<span>-- </span><span>The distance traveled in a certain time may increase or decrease.
-- The displacement covered in a certain time may increase or decrease.
-- The speed of the object may increase or decrease.
-- The velocity of the object (speed/direction) will change.
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Hope this helps..