Answer:
The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts
Explanation:
Electric potential is given as;
V = E*r
where;
E is the electric field strength, = kq/r²
V = ( kq/r²)*r
V = kq/r
k is coulomb's constant = 8.99 X 10⁹ Nm²/C²
q is the charge of the particles = 1.6 X 10⁻¹⁹ C
r is the distance between the particles = 859 nm
At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm
V = (8.99 X 10⁹ * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)
V = 3.349 X 10⁻³ Volts
Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts
Atomic Number = amount of protons. Atomic mass = protons (7) and neutrons (8)
Electrons will be the protons - any charge the isotope has. For example, a +2 charge would make the electrons 7- (+2) = 5. A -2 charge would be electrons 7 - (-2) = 9
Answer:
Explanation:
Let:
We need to know for which value of 
the function 
is equal to 
:
Therefore, we need to solve for the previous equation for :
Replacing the values of and :
Subtract 4 from both sides:
Multiply both sides by -1
Divide both sides by 3:
Therefore the value of for which is 
.
Verify the result:
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