All categories

3 years ago

Which of the following are likely to be affected by a magnet? Check all that apply.

Physics

2 answers:

Gelneren [198K]3 years ago

6 0

<h3><u>Answer;</u></h3>

C.An access card you scan for entry into a building

<h3><u>Explanation;</u></h3>

<em><u>Magnets are materials that have the capability of producing magnetic field.</u></em> Magnets attract magnetic material such as iron and cobalt while they don't have an effect on non-magnetic materials such as wood and plastic.
<em><u>Access cards are plastic cards with a microchip or a magnetic strip containing an encoded data that is read for an individual to gain entry into a building.</u></em>
<em><u>Due to the presence of a magnetic strip that is swiped through the mechanism in the door, they may be affected by magnetic field from the magnets.</u></em>

stellarik [79]3 years ago

5 0

I think the correct answers from the choices listed above are options B and C. A credit card and an access card you scan for entry into a building are most likely to be affected by a magnet. Hope this answers the question. Have a nice day.

You might be interested in

complete the analogy: 1. speed: velocity;______:______ a. acceleration:velocity b. distance:displacement c. speed:acceleration d

Paraphin [41]

Velocity is the vector,
made up of the scalar speed + direction of speed

b). Displacement is the vector,
made up of the scalar distance + direction of distance

7 0

3 years ago

Read 2 more answers

Table is in the picture. and will mark brainstest.

QveST [7]

B. A copper wire with rubber insulation

8 0

2 years ago

An electron is traveling at 0. 85c. what is its mass? (the rest mass is 9. 11 × 10-31 kg. )

egoroff_w [7]

The mass of the electron is $1.72\times 10^{-30}$ Kg.

<h3>How can we calculate the mass of the electron?</h3>

To calculate the mass of the electron we are using the formula,

$m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }$

Here we are given,

$m_0$ =The rest mass of an electron = $9. 11 \times 10^{-31}$ kg.

v= The velocity of electron = 0. 85c.

c= The velocity of light = c. (c= $3\times 10^8$ m/s)

We have to found the mass of an electron = m Kg.

Now we substitute the known values, we found that,

$m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-\frac{(0.85c)^{2} }{c^{2} } } }$

Or, $m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-(\frac{0.85c}{c})^2 } }$

Or, $m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-({0.85})^2 } }$

Or, $m=1.72\times 10^{-30}$ Kg.

From the above calculation we can conclude that, The mass of the electron is $1.72\times 10^{-30}$ Kg.

Learn more about electron:

brainly.com/question/860094

#SPJ4

4 0

1 year ago

A beam of light passes through a liquid into air. Angle 1, angle of

Ede4ka [16]

Answer: 1.57

Explanation:

This described situation is known as Refraction, a phenomenon in which light bends or changes its direction when passing through a medium with a index of refraction different from the other medium.

In this context, the index of refraction is a number that describes how fast light propagates through a medium or material.

According to Snell’s Law:

$n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})$ (1)