1. Let's call:
x: the width of the walkway.
b: 2x+16 (there is a widht "x" of the walkway on each side).
h: 2x+32 (there is a widht "x" of the walkway on each side).
A: 924 ft^2 ( the area of the pool of including the walkway).
2. The area of a rectangle is:
A=(b)(h)
b: the base of the rectangle (2x+16)
a: the height of the rectangle (2x+32)
3. Then, we have a quadratic equation:
924=(2x+16)(2x+32)
4x^2+64x+32x+512-924=0
4x^2+96x-412=0
4. We apply the quadratic formula to find the value of "x":
x=(-b±√(b^2-4ac))/2a
x=3.71
The answer is: The width of the walkway is 3.71 ft
The relation of t as in to what?
Answer:1875cm^3
Step-by-step explanation:
Volume = mass/density
15,000/8=1875
(First one)Low - 18
Q1 - 20
Median - 25
Q3 - 30
(Last one) High - 34
Answer:
<h2>152</h2>
Step-by-step explanation:
<h3>let x= 5 and y= 3</h3><h3 /><h3>x + y = 8</h3><h3>5 + 3 = 8</h3><h3 /><h3>xy = 15</h3><h3>5 × 3 = 15</h3><h3 /><h3>x³ + y³ = ?</h3><h3>5³ + 3³ = ?</h3><h3>125 + 27 = 152</h3>
