Hey there!
2x + 5(2 + 6x) + 3(2x - 7)
DISTRIBUTE
= 2x + 5(2) + 5(6x) + 3(2x) - 7
= 2x + 10 + 6x + 6x - 7
COMBINE the LIKE TERMS
= (2x + 6x + 6x) + (10 - 7)
= 2x + 6x + 6x + 10 - 7
= 8x + 6x + 10 - 7
= 14x + 3
Therefore, your answer is: 14x + 3
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
The answer is A.) The y-intercept of function f is greater than the y-intercept of function g.
1/4 =2/8+3/8 =5/8
1-5/8=3/8
The question says that the length of the floor of a room is 'y' meters.
Its width is 5 meters shorter than the length,
If the width is 5 meters shorter than the actual width should be:
meters
Now the room is in the shape of a rectangle, so we will use the formula of the perimeter of a rectangle:
Perimeter =
The length of the floor is 'y' meters
The width of the floor is 'y-5' meters
Plugging the values of length and width we get,
![2(y+ (y-5))](https://tex.z-dn.net/?f=2%28y%2B%20%28y-5%29%29)
Question says that the perimeter of the rectangle is
meters.
So,
![2(y+(y-5))=4y+1](https://tex.z-dn.net/?f=2%28y%2B%28y-5%29%29%3D4y%2B1)
We will solve for 'y'.
![2(y+y-5)=4y+1](https://tex.z-dn.net/?f=2%28y%2By-5%29%3D4y%2B1)
![2(2y-5)=4y+1](https://tex.z-dn.net/?f=2%282y-5%29%3D4y%2B1)
![4y-10=4y+1](https://tex.z-dn.net/?f=4y-10%3D4y%2B1)
Since,
![-10\neq 1](https://tex.z-dn.net/?f=-10%5Cneq%201)
The system of equation seems to have no solution.
Hence, no such floor exists.
Idk but just divide both of the fraction hope i helped you a little